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In a rectangle ABCD, AB= 15 cm angle BAC...

In a rectangle ABCD, AB= 15 cm `angle BAC = 60^@` then BC is equal to

A

`15 sqrt(3)`

B

`(15sqrt(3))/(2)`

C

`(15)/(sqrt(3))`

D

`(15)/(2 sqrt(3))`

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The correct Answer is:
To solve the problem, we need to find the length of side BC in rectangle ABCD, given that AB = 15 cm and angle BAC = 60°. ### Step-by-step Solution: 1. **Identify the triangle**: In rectangle ABCD, we can focus on triangle ABC. Here, AB is one side, and we need to find the length of side BC. 2. **Use the tangent function**: We know that in triangle ABC, angle BAC is given as 60°. We can use the tangent function, which relates the opposite side to the adjacent side in a right triangle. The formula for tangent is: \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \] In this case, angle BAC = 60°, the opposite side is BC, and the adjacent side is AB. 3. **Substitute the known values**: We can substitute the values we have into the tangent formula: \[ \tan(60°) = \frac{BC}{AB} \] Given that AB = 15 cm, we have: \[ \tan(60°) = \frac{BC}{15} \] 4. **Calculate tan(60°)**: The value of \(\tan(60°)\) is \(\sqrt{3}\). Therefore, we can rewrite the equation: \[ \sqrt{3} = \frac{BC}{15} \] 5. **Solve for BC**: To find BC, we can multiply both sides by 15: \[ BC = 15 \cdot \sqrt{3} \] 6. **Final answer**: Thus, the length of BC is: \[ BC = 15\sqrt{3} \text{ cm} \] ### Summary: The length of side BC in rectangle ABCD is \(15\sqrt{3}\) cm.
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