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If 3 tan theta =4, then find sqrt( (1- s...

If `3 tan theta =4`, then find `sqrt( (1- sin theta)/(1 + sin theta))`

A

`1/3`

B

`1/2`

C

`2/3`

D

none to these

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The correct Answer is:
To solve the problem, we need to find the value of \( \sqrt{\frac{1 - \sin \theta}{1 + \sin \theta}} \) given that \( 3 \tan \theta = 4 \). ### Step-by-Step Solution: 1. **Find \( \tan \theta \)**: \[ \tan \theta = \frac{4}{3} \] 2. **Identify the sides of the triangle**: - We can represent \( \tan \theta \) as \( \frac{\text{opposite}}{\text{adjacent}} \). Here, the opposite side (perpendicular) is 4 and the adjacent side (base) is 3. 3. **Use the Pythagorean theorem to find the hypotenuse**: \[ \text{hypotenuse}^2 = \text{opposite}^2 + \text{adjacent}^2 \] \[ \text{hypotenuse}^2 = 4^2 + 3^2 = 16 + 9 = 25 \] \[ \text{hypotenuse} = \sqrt{25} = 5 \] 4. **Calculate \( \sin \theta \)**: \[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{4}{5} \] 5. **Substitute \( \sin \theta \) into the expression**: \[ \sqrt{\frac{1 - \sin \theta}{1 + \sin \theta}} = \sqrt{\frac{1 - \frac{4}{5}}{1 + \frac{4}{5}}} \] 6. **Simplify the expression**: - Calculate \( 1 - \frac{4}{5} \): \[ 1 - \frac{4}{5} = \frac{1}{5} \] - Calculate \( 1 + \frac{4}{5} \): \[ 1 + \frac{4}{5} = \frac{9}{5} \] - Now substitute back: \[ \sqrt{\frac{\frac{1}{5}}{\frac{9}{5}}} = \sqrt{\frac{1}{5} \cdot \frac{5}{9}} = \sqrt{\frac{1}{9}} = \frac{1}{3} \] ### Final Answer: \[ \sqrt{\frac{1 - \sin \theta}{1 + \sin \theta}} = \frac{1}{3} \]
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