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The sum of factors of 1520 except the un...

The sum of factors of 1520 except the unity is :

A

3720

B

2730

C

2370

D

None of these

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The correct Answer is:
To find the sum of the factors of 1520 except for unity (1), we can follow these steps: ### Step 1: Find the prime factorization of 1520. To find the prime factors, we divide 1520 by the smallest prime numbers until we reach 1. - 1520 ÷ 2 = 760 - 760 ÷ 2 = 380 - 380 ÷ 2 = 190 - 190 ÷ 2 = 95 - 95 ÷ 5 = 19 - 19 ÷ 19 = 1 So, the prime factorization of 1520 is: \[ 1520 = 2^4 \times 5^1 \times 19^1 \] ### Step 2: Find all the factors of 1520. To find the factors, we can use the prime factorization. The factors can be generated by taking all combinations of the prime factors: The exponents of the prime factors are: - For \(2\): 0 to 4 (5 options) - For \(5\): 0 to 1 (2 options) - For \(19\): 0 to 1 (2 options) The total number of factors is given by multiplying the number of options: \[ (4+1)(1+1)(1+1) = 5 \times 2 \times 2 = 20 \] ### Step 3: List the factors of 1520. The factors of 1520 are: 1, 2, 4, 5, 8, 10, 16, 19, 20, 38, 40, 76, 95, 152, 190, 304, 380, 760, 1520 ### Step 4: Exclude unity (1) from the list of factors. Now we will exclude 1 from the list: 2, 4, 5, 8, 10, 16, 19, 20, 38, 40, 76, 95, 152, 190, 304, 380, 760, 1520 ### Step 5: Calculate the sum of the remaining factors. Now we will add all the factors except for 1: \[ 2 + 4 + 5 + 8 + 10 + 16 + 19 + 20 + 38 + 40 + 76 + 95 + 152 + 190 + 304 + 380 + 760 + 1520 \] Calculating this step by step: - \(2 + 4 = 6\) - \(6 + 5 = 11\) - \(11 + 8 = 19\) - \(19 + 10 = 29\) - \(29 + 16 = 45\) - \(45 + 19 = 64\) - \(64 + 20 = 84\) - \(84 + 38 = 122\) - \(122 + 40 = 162\) - \(162 + 76 = 238\) - \(238 + 95 = 333\) - \(333 + 152 = 485\) - \(485 + 190 = 675\) - \(675 + 304 = 979\) - \(979 + 380 = 1359\) - \(1359 + 760 = 2119\) - \(2119 + 1520 = 3639\) ### Final Answer: The sum of the factors of 1520 except for unity is **3639**. ---
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