Solve the following expressions .
`(-4)^3 xx 5^2 xx 7^0`

Answer

To solve the expression \((-4)^3 \times 5^2 \times 7^0\), we will follow these steps:

### Step 1: Evaluate \(7^0\)
According to the rules of exponents, any number raised to the power of 0 is equal to 1. Therefore:
\[ 7^0 = 1 \]

### Step 2: Rewrite the expression
Now we can rewrite the original expression by substituting \(7^0\) with 1:
\[ (-4)^3 \times 5^2 \times 1 \]
This simplifies to:
\[ (-4)^3 \times 5^2 \]

### Step 3: Calculate \((-4)^3\)
To calculate \((-4)^3\), we multiply \(-4\) by itself three times:
\[ (-4) \times (-4) \times (-4) = 16 \times (-4) = -64 \]

### Step 4: Calculate \(5^2\)
Now, we calculate \(5^2\):
\[ 5^2 = 5 \times 5 = 25 \]

### Step 5: Multiply the results
Now we multiply the results from Step 3 and Step 4:
\[ (-64) \times 25 \]
To perform this multiplication:
\[ -64 \times 25 = -1600 \]

### Final Result
Thus, the final answer for the expression \((-4)^3 \times 5^2 \times 7^0\) is:
\[ \boxed{-1600} \]

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