Find the remainder when `38 + 71 + 85` is divided by 16.

Answer

To find the remainder when \( 38 + 71 + 85 \) is divided by 16, we can follow these steps:

### Step 1: Calculate the individual remainders
We will find the remainder of each number when divided by 16.

1. **For 38**:
\[ 38 \div 16 = 2 \quad \text{(since } 16 \times 2 = 32\text{)} \]
The remainder is:
\[ 38 - 32 = 6 \]

2. **For 71**:
\[ 71 \div 16 = 4 \quad \text{(since } 16 \times 4 = 64\text{)} \]
The remainder is:
\[ 71 - 64 = 7 \]

3. **For 85**:
\[ 85 \div 16 = 5 \quad \text{(since } 16 \times 5 = 80\text{)} \]
The remainder is:
\[ 85 - 80 = 5 \]

### Step 2: Add the remainders
Now, we will add the remainders we found:
\[ 6 + 7 + 5 = 18 \]

### Step 3: Find the remainder of the sum when divided by 16
Next, we need to find the remainder when 18 is divided by 16:
\[ 18 \div 16 = 1 \quad \text{(since } 16 \times 1 = 16\text{)} \]
The remainder is:
\[ 18 - 16 = 2 \]

### Final Answer
Thus, the remainder when \( 38 + 71 + 85 \) is divided by 16 is \( \boxed{2} \).

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