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If 1, omega, omega^2 be the cube roots o...

If `1, omega, omega^2` be the cube roots of unity, then the value of `(1 - omega + omega^2)^(5) + (1 + omega - omega^2)^5` is :

A

a) 0

B

b )16

C

c) 32

D

d) 64

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The correct Answer is:
To solve the problem, we need to evaluate the expression \( (1 - \omega + \omega^2)^5 + (1 + \omega - \omega^2)^5 \), where \( 1, \omega, \omega^2 \) are the cube roots of unity. ### Step-by-Step Solution: 1. **Understanding Cube Roots of Unity**: The cube roots of unity are defined as: \[ 1 + \omega + \omega^2 = 0 \] This implies that: \[ \omega + \omega^2 = -1 \] 2. **Simplifying the First Term**: We start with the first term: \[ 1 - \omega + \omega^2 \] Substituting \( \omega + \omega^2 = -1 \): \[ 1 - \omega + \omega^2 = 1 - \omega + (-1 - \omega) = 1 - \omega - 1 - \omega = -2\omega \] 3. **Calculating the First Power**: Now we raise this to the power of 5: \[ (1 - \omega + \omega^2)^5 = (-2\omega)^5 = -32\omega^5 \] Since \( \omega^3 = 1 \), we have: \[ \omega^5 = \omega^{3+2} = \omega^2 \] Thus: \[ (1 - \omega + \omega^2)^5 = -32\omega^2 \] 4. **Simplifying the Second Term**: Now, we simplify the second term: \[ 1 + \omega - \omega^2 \] Again substituting \( \omega + \omega^2 = -1 \): \[ 1 + \omega - \omega^2 = 1 + \omega + (-1 - \omega) = 1 + \omega - 1 - \omega = 0 \] Thus: \[ (1 + \omega - \omega^2)^5 = 0^5 = 0 \] 5. **Combining Both Terms**: Now we combine both results: \[ (1 - \omega + \omega^2)^5 + (1 + \omega - \omega^2)^5 = -32\omega^2 + 0 = -32\omega^2 \] 6. **Final Evaluation**: To find the final value, we note that \( \omega^2 \) is one of the cube roots of unity. We can express the final result in terms of \( \omega \): \[ -32\omega^2 \] ### Conclusion: The value of \( (1 - \omega + \omega^2)^5 + (1 + \omega - \omega^2)^5 \) is \( -32\omega^2 \).
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