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The number of two digit numbers which on...

The number of two digit numbers which on being reversed (i.e., their digits exchanged the position) gives out perfect square two digit numbers:

A

1

B

4

C

6

D

10

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of two-digit numbers that, when reversed, result in perfect square two-digit numbers, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Two-Digit Perfect Squares**: First, we need to identify all the two-digit perfect squares. The perfect squares are obtained by squaring integers. The smallest two-digit perfect square is \(4^2 = 16\) and the largest is \(9^2 = 81\). The two-digit perfect squares are: - \(16\) (from \(4^2\)) - \(25\) (from \(5^2\)) - \(36\) (from \(6^2\)) - \(49\) (from \(7^2\)) - \(64\) (from \(8^2\)) - \(81\) (from \(9^2\)) 2. **Reverse the Digits of Each Perfect Square**: Next, we will reverse the digits of each of these perfect squares: - \(16\) reversed is \(61\) - \(25\) reversed is \(52\) - \(36\) reversed is \(63\) - \(49\) reversed is \(94\) - \(64\) reversed is \(46\) - \(81\) reversed is \(18\) 3. **Count the Valid Two-Digit Numbers**: Now, we need to count how many of these reversed numbers are valid two-digit numbers: - \(61\) (valid) - \(52\) (valid) - \(63\) (valid) - \(94\) (valid) - \(46\) (valid) - \(18\) (valid) All six reversed numbers are valid two-digit numbers. 4. **Conclusion**: Therefore, the total number of two-digit numbers which, when reversed, give perfect square two-digit numbers is \(6\). ### Final Answer: The answer is \(6\). ---
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