Home
Class 14
MATHS
When a 3 digit number 984 is added to an...

When a 3 digit number 984 is added to another 3 digit number 4 p3, we get a four digit number 13q7, which is divisible by 11. The value of `p + q` is :

A

10

B

11

C

12

D

13

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to follow the given information carefully. ### Step 1: Understand the numbers involved We have two numbers: - The first number is 984. - The second number is represented as 4p3, where p is a digit we need to find. When we add these two numbers, we get a four-digit number represented as 13q7, where q is another digit we need to find. ### Step 2: Set up the equation We can express the addition as: \[ 984 + 4p3 = 13q7 \] ### Step 3: Calculate the sum of the numbers First, we need to convert 4p3 into a numerical form: - 4p3 = 400 + 10p + 3 Now, we can rewrite the equation: \[ 984 + (400 + 10p + 3) = 1300 + 10q + 7 \] This simplifies to: \[ 984 + 403 + 10p = 1300 + 10q + 7 \] \[ 1387 + 10p = 1300 + 10q \] ### Step 4: Rearranging the equation Now, we can rearrange the equation to isolate terms involving p and q: \[ 10p - 10q = 1300 - 1387 \] \[ 10p - 10q = -87 \] Dividing the entire equation by 10 gives: \[ p - q = -8.7 \] Since p and q are digits, we can express this as: \[ p - q = -8 \] or \[ p = q - 8 \] ### Step 5: Use the divisibility rule of 11 Next, we need to check the divisibility of the number 13q7 by 11. According to the rule of divisibility for 11, the difference between the sum of the digits in odd positions and the sum of the digits in even positions should be either 0 or a multiple of 11. The digits in 13q7 are: - Odd positions: 1 (1st) + q (3rd) + 7 (4th) = 1 + q + 7 = q + 8 - Even positions: 3 (2nd) + 7 (4th) = 3 + 7 = 10 Now, we calculate the difference: \[ (q + 8) - 10 = q - 2 \] ### Step 6: Set up the divisibility condition For the number to be divisible by 11: \[ q - 2 = 0 \quad \text{or} \quad q - 2 = 11k \quad (k \text{ is an integer}) \] The only feasible value for q (since it is a digit) is: \[ q - 2 = 0 \] Thus, \[ q = 2 \] ### Step 7: Substitute q back to find p Now that we have q, we can find p using the earlier equation: \[ p = q - 8 \] \[ p = 2 - 8 = -6 \] This is not a valid digit. Therefore, we need to check for other values of q that satisfy the divisibility condition. ### Step 8: Check for valid values of q Let's check for other values of q: If we set \( q = 9 \): \[ p = 9 - 8 = 1 \] ### Step 9: Calculate p + q Now we have: - p = 1 - q = 9 Thus, the value of \( p + q \) is: \[ p + q = 1 + 9 = 10 \] ### Final Answer The value of \( p + q \) is **10**. ---
Promotional Banner

Topper's Solved these Questions

  • FUNDAMENTALS

    ARIHANT SSC|Exercise INTRODUCTORY EXERCISE - 1.2|16 Videos
  • FUNDAMENTALS

    ARIHANT SSC|Exercise INTRODUCTORY EXERCISE - 1.3|3 Videos
  • FUNDAMENTALS

    ARIHANT SSC|Exercise TEST OF YOU - LEARNING - 2|40 Videos
  • FUNCTIONS AND GRAPH

    ARIHANT SSC|Exercise Final Round|40 Videos
  • GEOMETRY

    ARIHANT SSC|Exercise EXERCISE(LEVEL 2)|52 Videos

Similar Questions

Explore conceptually related problems

A 3 -digit number 4a3 is added to another 3- digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then (a+b) is (a) 10 (b) 11 (c) 12 (d) 15

A three digit number 3a5 is added to another 3-digit number 933 to give a 4-digit number 12b8, which is divisible-by 11. Then, find the value of a+b ?

If a three digit number 7X6 is divisible by 11, then the value of X is :

If a three digit number 7X6 is divisible by 11, then the value of X is

A 3 -digit number 4p3 is added to 984 to get a 4 -digit number 13q7. If 13q7 is divisible by 11, then (p+q)=?

The seven digit number 876p37q is divisible by 225. The values of p and q can be respectively

The number of 3-digit numbers divisible by 7 is

Find the sum of all 3 – digit natural numbers, which are divisible by 13.

If the sum of the digits in a number is a _____ of 3, then the number is divisible by 3.

ARIHANT SSC-FUNDAMENTALS -INTRODUCTORY EXERCISE - 1.1
  1. Total number of numbers lying in the range of 1331 and 3113 which are ...

    Text Solution

    |

  2. Atleast what number must be subtracted from 434079 so that is becomes ...

    Text Solution

    |

  3. Atleast what number must be subtracted from 434079 so that is becomes ...

    Text Solution

    |

  4. Which one number is closest to 193 which is divisible by 18 is :

    Text Solution

    |

  5. The product o two numbers ab7 and cd5 could be where ab7 and cd5 are i...

    Text Solution

    |

  6. When a 3 digit number 984 is added to another 3 digit number 4 p3, we ...

    Text Solution

    |

  7. When a number divided by 9235, we get the quotient 888 and the remaind...

    Text Solution

    |

  8. The number which when divided by 33 is perfectly divisible and closer ...

    Text Solution

    |

  9. A number which when 'divided by 32 leaves a remainder of 29. If this n...

    Text Solution

    |

  10. A number when divided by 5 leaves a remainder of 4, when the double (i...

    Text Solution

    |

  11. When a number 'N' is divided by a proper divisor 'D' then it leaves a ...

    Text Solution

    |

  12. A number when divided by 5 gives a number which is 8 more than the rem...

    Text Solution

    |

  13. When a natural number divided by a certain divisor, we get 15 as a rem...

    Text Solution

    |

  14. A certain number 'C' when divided by N1 it leaves a remainder of 13 an...

    Text Solution

    |

  15. In the above problem the value of c is :

    Text Solution

    |

  16. In how many parts a rod of length 19.5 m can be broken of equal length...

    Text Solution

    |

  17. six digit number which is consisting of only one digits either 1,2,3,4...

    Text Solution

    |

  18. The maximum possible difference between the 4 digit numbers formed by ...

    Text Solution

    |

  19. The sum of all digits except the unity that can be substituted at the ...

    Text Solution

    |

  20. A certain number N when multiplied by 13, the resultant values consist...

    Text Solution

    |