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A certain number 'C' when divided by N1 ...

A certain number 'C' when divided by `N_1` it leaves a remainder of 13 and when it is divided by `N_2` it leaves a remainder of 1, where `N_1` and `N_2` are the positive integers. Then the value of `N_1 + N_2` is if `(N_1)/(N_2) = 5/4`.

A

36

B

27

C

54

D

can't be determined uniquely

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The correct Answer is:
To solve the problem step by step, we will use the information provided in the question and the relationships between the numbers. ### Step 1: Set Up the Equations Given: 1. \( C \equiv 13 \mod N_1 \) (C leaves a remainder of 13 when divided by \( N_1 \)) 2. \( C \equiv 1 \mod N_2 \) (C leaves a remainder of 1 when divided by \( N_2 \)) 3. The ratio \( \frac{N_1}{N_2} = \frac{5}{4} \) From the first equation, we can express \( C \) as: \[ C = kN_1 + 13 \] for some integer \( k \). From the second equation, we can express \( C \) as: \[ C = mN_2 + 1 \] for some integer \( m \). ### Step 2: Equate the Two Expressions for C Since both expressions equal \( C \), we can set them equal to each other: \[ kN_1 + 13 = mN_2 + 1 \] Rearranging gives us: \[ kN_1 - mN_2 = -12 \] or \[ kN_1 = mN_2 - 12 \] ### Step 3: Express N1 in Terms of N2 From the ratio \( \frac{N_1}{N_2} = \frac{5}{4} \), we can express \( N_1 \) in terms of \( N_2 \): \[ N_1 = \frac{5}{4} N_2 \] ### Step 4: Substitute N1 into the Equation Substituting \( N_1 \) into the equation \( kN_1 - mN_2 = -12 \): \[ k\left(\frac{5}{4}N_2\right) - mN_2 = -12 \] This simplifies to: \[ \frac{5k}{4}N_2 - mN_2 = -12 \] Factoring out \( N_2 \): \[ N_2\left(\frac{5k}{4} - m\right) = -12 \] ### Step 5: Solve for N2 From this equation, we can express \( N_2 \) as: \[ N_2 = \frac{-12}{\frac{5k}{4} - m} \] ### Step 6: Find N1 and N2 Since \( N_2 \) must be a positive integer, \( \frac{5k}{4} - m \) must be a negative integer, which means \( m \) must be greater than \( \frac{5k}{4} \). Now, let's express \( N_1 \) in terms of \( k \): \[ N_1 = \frac{5}{4}N_2 = \frac{5}{4} \cdot \frac{-12}{\frac{5k}{4} - m} \] ### Step 7: Calculate N1 + N2 Now we can find \( N_1 + N_2 \): \[ N_1 + N_2 = N_2\left(\frac{5}{4} + 1\right) = N_2 \cdot \frac{9}{4} \] Substituting \( N_2 \): \[ N_1 + N_2 = \frac{-12}{\frac{5k}{4} - m} \cdot \frac{9}{4} \] ### Step 8: Determine Values To find specific integer values for \( N_1 \) and \( N_2 \), we can try different integer values for \( k \) and \( m \) that satisfy the conditions. ### Final Step: Conclusion After testing various integers, we can find that: - If \( N_1 = 20 \) and \( N_2 = 16 \), then \( N_1 + N_2 = 36 \). - Therefore, the answer is \( N_1 + N_2 = 36 \).
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