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(6^6 + 6^6 + 6^6 + 6^6 + 6^6 + 6^6)/(3^6...

`(6^6 + 6^6 + 6^6 + 6^6 + 6^6 + 6^6)/(3^6 + 3^6 + 3^6) div (4^6 + 4^6 + 4^6 + 4^6)/(2^6 + 2^6) = 2^n` , then the value of n is :

A

`-1`

B

`0`

C

`1/2`

D

`1`

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AI Generated Solution

The correct Answer is:
To solve the expression \[ \frac{(6^6 + 6^6 + 6^6 + 6^6 + 6^6 + 6^6)}{(3^6 + 3^6 + 3^6)} \div \frac{(4^6 + 4^6 + 4^6 + 4^6)}{(2^6 + 2^6)} = 2^n, \] we will simplify each part step by step. ### Step 1: Simplify the numerator of the first fraction The numerator of the first fraction is \(6^6 + 6^6 + 6^6 + 6^6 + 6^6 + 6^6\). Since there are 6 terms of \(6^6\), we can write it as: \[ 6 \times 6^6 = 6^1 \times 6^6 = 6^{1+6} = 6^7. \] **Hint for Step 1:** Remember that adding the same number multiple times is equivalent to multiplying that number by the count of terms. ### Step 2: Simplify the denominator of the first fraction The denominator of the first fraction is \(3^6 + 3^6 + 3^6\). There are 3 terms of \(3^6\), so we can write it as: \[ 3 \times 3^6 = 3^1 \times 3^6 = 3^{1+6} = 3^7. \] **Hint for Step 2:** Use the same principle of multiplication for addition of identical terms. ### Step 3: Write the first fraction Now we can rewrite the first fraction: \[ \frac{6^7}{3^7}. \] **Hint for Step 3:** When simplifying fractions, remember that you can express them in terms of powers. ### Step 4: Simplify the first fraction We can simplify \(\frac{6^7}{3^7}\) as follows: \[ \left(\frac{6}{3}\right)^7 = 2^7. \] **Hint for Step 4:** When dividing powers with the same exponent, you can divide the bases first. ### Step 5: Simplify the numerator of the second fraction The numerator of the second fraction is \(4^6 + 4^6 + 4^6 + 4^6\). There are 4 terms of \(4^6\), so we can write it as: \[ 4 \times 4^6 = 4^1 \times 4^6 = 4^{1+6} = 4^7. \] **Hint for Step 5:** Again, apply the multiplication principle for identical terms. ### Step 6: Simplify the denominator of the second fraction The denominator of the second fraction is \(2^6 + 2^6\). There are 2 terms of \(2^6\), so we can write it as: \[ 2 \times 2^6 = 2^1 \times 2^6 = 2^{1+6} = 2^7. \] **Hint for Step 6:** Keep using the multiplication principle for addition. ### Step 7: Write the second fraction Now we can rewrite the second fraction: \[ \frac{4^7}{2^7}. \] **Hint for Step 7:** Keep the fractions in terms of their bases for easier simplification. ### Step 8: Simplify the second fraction We can simplify \(\frac{4^7}{2^7}\) as follows: \[ \left(\frac{4}{2}\right)^7 = 2^7. \] **Hint for Step 8:** Again, simplify the bases before applying the exponent. ### Step 9: Combine both parts Now we have: \[ \frac{6^7}{3^7} \div \frac{4^7}{2^7} = 2^7 \div 2^7. \] **Hint for Step 9:** Remember that dividing powers with the same base involves subtracting the exponents. ### Step 10: Final simplification This simplifies to: \[ 2^{7-7} = 2^0 = 1. \] ### Step 11: Set equal to \(2^n\) Now we have: \[ 1 = 2^n. \] This implies: \[ n = 0. \] ### Final Answer The value of \(n\) is: \[ \boxed{0}. \]
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ARIHANT SSC-FUNDAMENTALS -EXERCISE - MISCELLANEOUS
  1. If 4^(x + 3) xx 2^(x - 3) - 128 = 0 then the value of x is :

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  2. If a^m .a^n = a^(mn), then m(n - 2) + n(m- 2) is :

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  3. (6^6 + 6^6 + 6^6 + 6^6 + 6^6 + 6^6)/(3^6 + 3^6 + 3^6) div (4^6 + 4^6 +...

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  4. If a^(1//m) = b^(1//n) = c^(1//p) and abc = 1 then m + n + p is equal...

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  5. Which one of the following among the numbers -3/7, 2/3 and (-1)/3 is i...

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  6. A rational equivalent to (-24)/20 with denominator 25 is :

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  7. 3/4 xx ((-2)/3 + 3/5) is equal to :

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  8. In a problem involving division, the divisor is eight times the quotie...

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  9. Which one of the following is not correct ?

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  10. Let a/b = c/d, (where a and b are odd prime numbers) . If c > a and d ...

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  11. Which one of the following numbers belong to the given series 18,26, 3...

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  12. The number of prime factors in the expression 6^4 xx 8^6 xx 10^8 xx 12...

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  13. x is a five digit number. The digit in ten thousands place is 1. The n...

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  14. The sum of all possible factors of 500 (including 1 and 500 themselves...

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  15. HCF of 1007 and 1273 is :

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  16. If 2s = 9 then the value of s^2 + (s - 1)^2 + (s - 3)^2 + (s - 5)^2 ...

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  17. The sum of the digits of a two digit number is 8. The number obtained ...

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  18. If x^y = y^x and y = 2x then x is equal to :

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  19. Value of [(x^l)^(1 - 1/l)]^(1/(l - 1)) is:

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  20. If x^a xx x^b xx x^c = 1, then a^3 + b^3 + c^3 is equal to :

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