The divisor when the quotient, dividend and the remainder are respectively 547, 171282 and 71 is equal to :

Options

A. 333
B. 323
C. 313
D. 303

Answer

To find the divisor when the quotient, dividend, and remainder are given as 547, 171282, and 71 respectively, we can use the formula:

**Dividend = (Divisor × Quotient) + Remainder**

Let's denote:
- Dividend (D) = 171282
- Quotient (Q) = 547
- Remainder (R) = 71
- Divisor (d) = ?

We need to rearrange the formula to solve for the divisor (d):

1. Start with the formula:
\[ D = (d \times Q) + R \]

2. Substitute the known values into the equation:
\[ 171282 = (d \times 547) + 71 \]

3. To isolate the term with the divisor, subtract the remainder from both sides:
\[ 171282 - 71 = d \times 547 \]

4. Calculate the left side:
\[ 171211 = d \times 547 \]

5. Now, to find the divisor (d), divide both sides by 547:
\[ d = \frac{171211}{547} \]

6. Perform the division:
\[ d = 313 \]

Thus, the divisor is **313**.