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If 3^n = 27 then 3^(n - 2) is:...

If `3^n = 27` then `3^(n - 2)` is:

A

3

B

`1/3`

C

`1/9`

D

`9`

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AI Generated Solution

The correct Answer is:
To solve the equation \( 3^n = 27 \) and find the value of \( 3^{(n - 2)} \), we can follow these steps: ### Step 1: Rewrite 27 as a power of 3 We know that \( 27 \) can be expressed as a power of \( 3 \): \[ 27 = 3^3 \] ### Step 2: Set the exponents equal Since the bases are the same, we can set the exponents equal to each other: \[ n = 3 \] ### Step 3: Substitute \( n \) into \( 3^{(n - 2)} \) Now that we have found \( n \), we can substitute it into the expression \( 3^{(n - 2)} \): \[ 3^{(n - 2)} = 3^{(3 - 2)} = 3^{1} \] ### Step 4: Calculate \( 3^{1} \) Now we can calculate \( 3^{1} \): \[ 3^{1} = 3 \] ### Final Answer Thus, the value of \( 3^{(n - 2)} \) is: \[ \boxed{3} \] ---
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ARIHANT SSC-FUNDAMENTALS -EXERCISE - MISCELLANEOUS
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  4. If a = b^x , b = c^y, c = a^z, then xyz is :

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