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9^(3//2) div (243)^(-2//3) simplifies to...

`9^(3//2) div (243)^(-2//3)` simplifies to :

A

`3^(10//3)`

B

`3^(19//3)`

C

`3^(1//3)`

D

`3^(19)`

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The correct Answer is:
To simplify the expression \( 9^{\frac{3}{2}} \div (243)^{-\frac{2}{3}} \), we will follow these steps: ### Step 1: Rewrite the bases in terms of powers of 3 We know that: - \( 9 = 3^2 \) - \( 243 = 3^5 \) So we can rewrite the expression as: \[ (3^2)^{\frac{3}{2}} \div (3^5)^{-\frac{2}{3}} \] ### Step 2: Apply the power of a power property Using the property \( (a^m)^n = a^{m \cdot n} \), we simplify both parts: \[ (3^2)^{\frac{3}{2}} = 3^{2 \cdot \frac{3}{2}} = 3^3 \] \[ (3^5)^{-\frac{2}{3}} = 3^{5 \cdot -\frac{2}{3}} = 3^{-\frac{10}{3}} \] So now we have: \[ 3^3 \div 3^{-\frac{10}{3}} \] ### Step 3: Apply the division of powers property Using the property \( a^m \div a^n = a^{m-n} \), we combine the powers: \[ 3^3 \div 3^{-\frac{10}{3}} = 3^{3 - (-\frac{10}{3})} = 3^{3 + \frac{10}{3}} \] ### Step 4: Simplify the exponent To add \( 3 \) and \( \frac{10}{3} \), we first convert \( 3 \) into a fraction with a common denominator: \[ 3 = \frac{9}{3} \] Now we can add: \[ \frac{9}{3} + \frac{10}{3} = \frac{19}{3} \] ### Step 5: Write the final result Thus, we have: \[ 3^{\frac{19}{3}} \] ### Final Answer The simplified expression is: \[ 3^{\frac{19}{3}} \] ---
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ARIHANT SSC-FUNDAMENTALS -EXERCISE - MISCELLANEOUS
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  3. 9^(3//2) div (243)^(-2//3) simplifies to :

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