Home
Class 14
MATHS
The sum of all four digit numbers which ...

The sum of all four digit numbers which are divisible by 7 is :

A

7071071

B

`7^7`

C

`7107073`

D

`10019996`

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of all four-digit numbers that are divisible by 7, we can follow these steps: ### Step 1: Identify the smallest four-digit number divisible by 7 The smallest four-digit number is 1000. We need to find the smallest four-digit number that is divisible by 7. 1. Divide 1000 by 7: \[ 1000 \div 7 = 142 \quad \text{(remainder 6)} \] This means that 1000 is not divisible by 7. 2. To find the smallest four-digit number divisible by 7, we subtract the remainder from 1000: \[ 1000 - 6 = 994 \quad \text{(not a four-digit number)} \] So, we add 7 to 994: \[ 994 + 7 = 1001 \] Thus, the smallest four-digit number divisible by 7 is **1001**. ### Step 2: Identify the largest four-digit number divisible by 7 The largest four-digit number is 9999. We need to find the largest four-digit number that is divisible by 7. 1. Divide 9999 by 7: \[ 9999 \div 7 = 1428 \quad \text{(remainder 3)} \] This means that 9999 is not divisible by 7. 2. To find the largest four-digit number divisible by 7, we subtract the remainder from 9999: \[ 9999 - 3 = 9996 \] Thus, the largest four-digit number divisible by 7 is **9996**. ### Step 3: Determine the number of terms in the sequence The sequence of four-digit numbers divisible by 7 forms an arithmetic progression (AP) where: - First term \(a = 1001\) - Last term \(l = 9996\) - Common difference \(d = 7\) To find the number of terms \(n\), we can use the formula for the \(n\)th term of an AP: \[ l = a + (n - 1) \cdot d \] Substituting the known values: \[ 9996 = 1001 + (n - 1) \cdot 7 \] Rearranging gives: \[ 9996 - 1001 = (n - 1) \cdot 7 \] \[ 8995 = (n - 1) \cdot 7 \] \[ n - 1 = \frac{8995}{7} \] Calculating: \[ n - 1 = 1285 \quad \Rightarrow \quad n = 1286 \] ### Step 4: Calculate the sum of the arithmetic series The sum \(S_n\) of the first \(n\) terms of an AP can be calculated using the formula: \[ S_n = \frac{n}{2} \cdot (a + l) \] Substituting the values we found: \[ S_{1286} = \frac{1286}{2} \cdot (1001 + 9996) \] Calculating: \[ S_{1286} = 643 \cdot 10997 \] Now, performing the multiplication: \[ S_{1286} = 7071071 \] ### Conclusion The sum of all four-digit numbers that are divisible by 7 is **7071071**. ---
Promotional Banner

Topper's Solved these Questions

  • FUNDAMENTALS

    ARIHANT SSC|Exercise LEVEL 2|123 Videos
  • FUNDAMENTALS

    ARIHANT SSC|Exercise FINAL ROUND|116 Videos
  • FUNDAMENTALS

    ARIHANT SSC|Exercise EXERCISE - MISCELLANEOUS|140 Videos
  • FUNCTIONS AND GRAPH

    ARIHANT SSC|Exercise Final Round|40 Videos
  • GEOMETRY

    ARIHANT SSC|Exercise EXERCISE(LEVEL 2)|52 Videos

Similar Questions

Explore conceptually related problems

The number of all four digit numbers which are divisible by 4 that can be formed from the digits 1, 2, 3, 4, and 5, is

The sum of all the 3 digit numbers is

Find the sum of all two digit natural numbers which are divisible by 4.

find the sum of all three digit natural numbers which are divisible by 7

Find the sum of all three digit natural numbers,which are divisible by 7.

Find the sum of all 3 – digit natural numbers, which are divisible by 13.

Find the sum of all three-digit natural numbers,which are divisible by 7.

ARIHANT SSC-FUNDAMENTALS -LEVEL 1
  1. The remainder when 2^(39) is divided by 39 is :

    Text Solution

    |

  2. The unit digit of the following expression (1 !)^(99) + (2!)^(98) + ...

    Text Solution

    |

  3. The sum of all four digit numbers which are divisible by 7 is :

    Text Solution

    |

  4. When the numerator of a positive fraction is incresed by 2 and the den...

    Text Solution

    |

  5. In the given expression pq = p - q + 9, q is a fraction and p is any p...

    Text Solution

    |

  6. The digits of a three digit number are in G.P. when the digits of this...

    Text Solution

    |

  7. How many even integers n; 13 <=n<=313 are of the form of 3k +4, where ...

    Text Solution

    |

  8. In the above question the number of values of n which are odd:

    Text Solution

    |

  9. if a and b are two odd distinct prime numbers and if a > b then a^2 -...

    Text Solution

    |

  10. If P = (101)^(100) and Q = (100)^(101), then the correct relation is:

    Text Solution

    |

  11. If k^2 - 25 is an odd integer then which one of the following values g...

    Text Solution

    |

  12. (a + 1)(b-1) = 625, (a != b) in I^(+) then the value of (a +b) is

    Text Solution

    |

  13. If p+1/p=q, then for p > 0

    Text Solution

    |

  14. If a^b = b^a, (a != b) > 1, then the value of (a div b) is :

    Text Solution

    |

  15. If m^n - n^m = (m + n), (m, n) in prime numbers, then what can be said...

    Text Solution

    |

  16. There is unique 3 digit number which is cube of a natural number, if w...

    Text Solution

    |

  17. The give expression n^4 - n^2 is divisible by for n in I^+ and n > 2:

    Text Solution

    |

  18. If a, b represents two distinct positive integers and thus (aa)^b = ab...

    Text Solution

    |

  19. At out training institute we have p - 1, p - 2, p - 3 and p - 4 proces...

    Text Solution

    |

  20. If n is natural number (greater than one) then (392)^n - (392)^(n -1) ...

    Text Solution

    |