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If a^b = b^a, (a != b) > 1, then the val...

If `a^b = b^a, (a != b) > 1`, then the value of `(a div b)` is :

A

5

B

6

C

7

D

does not exist

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AI Generated Solution

The correct Answer is:
To solve the equation \( a^b = b^a \) with the condition that \( a \neq b \) and both \( a \) and \( b \) are greater than 1, we can follow these steps: ### Step 1: Take the logarithm of both sides We start by taking the logarithm of both sides of the equation: \[ \log(a^b) = \log(b^a) \] ### Step 2: Apply the power rule of logarithms Using the power rule of logarithms, we can rewrite the equation as: \[ b \cdot \log(a) = a \cdot \log(b) \] ### Step 3: Rearrange the equation Now, we can rearrange this equation to isolate the ratio of \( a \) and \( b \): \[ \frac{\log(a)}{a} = \frac{\log(b)}{b} \] ### Step 4: Let \( k \) be the common value Let \( k \) be the common value of \( \frac{\log(a)}{a} \) and \( \frac{\log(b)}{b} \): \[ \log(a) = k \cdot a \quad \text{and} \quad \log(b) = k \cdot b \] ### Step 5: Divide the equations Now, we can divide the two equations: \[ \frac{\log(a)}{\log(b)} = \frac{k \cdot a}{k \cdot b} = \frac{a}{b} \] ### Step 6: Solve for \( \frac{a}{b} \) This gives us: \[ \frac{a}{b} = \frac{\log(a)}{\log(b)} \] ### Step 7: Identify specific values To find specific values of \( a \) and \( b \), we can use known pairs that satisfy \( a^b = b^a \). A well-known pair is \( (2, 4) \) or \( (4, 2) \). ### Step 8: Calculate \( \frac{a}{b} \) For \( a = 4 \) and \( b = 2 \): \[ \frac{a}{b} = \frac{4}{2} = 2 \] ### Conclusion Thus, the value of \( \frac{a}{b} \) is \( 2 \). ---
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