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The possible value of |x| + |x - 1| = 2 ...

The possible value of `|x| + |x - 1| = 2` is :

A

`(3/2, -1/2}`

B

`{3/2, 1/2}`

C

`{3/2, - 1/2}`

D

None of these

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The correct Answer is:
To solve the equation \( |x| + |x - 1| = 2 \), we will consider different cases based on the value of \( x \). ### Step 1: Consider the case when \( x < 0 \) In this case, both \( |x| \) and \( |x - 1| \) can be expressed as: - \( |x| = -x \) (since \( x \) is negative) - \( |x - 1| = -(x - 1) = -x + 1 \) (since \( x - 1 \) is also negative) Substituting these into the equation gives: \[ -x + (-x + 1) = 2 \] This simplifies to: \[ -2x + 1 = 2 \] Subtracting 1 from both sides: \[ -2x = 1 \] Dividing by -2: \[ x = -\frac{1}{2} \] ### Step 2: Consider the case when \( 0 \leq x < 1 \) In this case: - \( |x| = x \) (since \( x \) is non-negative) - \( |x - 1| = -(x - 1) = -x + 1 \) (since \( x - 1 \) is negative) Substituting these into the equation gives: \[ x + (-x + 1) = 2 \] This simplifies to: \[ 1 = 2 \] This is a contradiction, so there are no solutions in this case. ### Step 3: Consider the case when \( x \geq 1 \) In this case: - \( |x| = x \) - \( |x - 1| = x - 1 \) (since \( x - 1 \) is non-negative) Substituting these into the equation gives: \[ x + (x - 1) = 2 \] This simplifies to: \[ 2x - 1 = 2 \] Adding 1 to both sides: \[ 2x = 3 \] Dividing by 2: \[ x = \frac{3}{2} \] ### Conclusion The possible values of \( x \) that satisfy the equation \( |x| + |x - 1| = 2 \) are: - \( x = -\frac{1}{2} \) - \( x = \frac{3}{2} \) ### Final Answer The possible values of \( x \) are \( -\frac{1}{2} \) and \( \frac{3}{2} \). ---
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