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If (pqr)^2 = (ijk pqr), where i,j,k,p,q,...

If `(pqr)^2 = (ijk pqr),` where `i,j,k,p,q,r in W,` are pqr and ijkpqr are three digits and 6 digits numbers respectively. Then the value of `i xx j xx k xx p xx q xx r ` is :

A

0

B

720

C

can't say

D

None of these

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AI Generated Solution

The correct Answer is:
To solve the equation \((pqr)^2 = (ijkpqr)\), where \(pqr\) is a three-digit number and \(ijkpqr\) is a six-digit number, we need to follow these steps: ### Step 1: Understand the Range of \(pqr\) Since \(pqr\) is a three-digit number, it must be in the range of 100 to 999. ### Step 2: Determine the Range of \((pqr)^2\) Next, we calculate the square of the smallest and largest three-digit numbers: - The smallest three-digit number is \(100\): \[ (100)^2 = 10000 \] - The largest three-digit number is \(999\): \[ (999)^2 = 998001 \] Thus, \((pqr)^2\) must be a six-digit number, which means it must be between \(100000\) and \(999999\). ### Step 3: Set the Condition for \(ijkpqr\) The six-digit number \(ijkpqr\) can be expressed as: \[ ijkpqr = 1000 \times ijk + pqr \] This means that \((pqr)^2\) must equal \(1000 \times ijk + pqr\). ### Step 4: Rearranging the Equation Rearranging gives us: \[ (pqr)^2 - pqr = 1000 \times ijk \] Factoring out \(pqr\) on the left side: \[ pqr(pqr - 1) = 1000 \times ijk \] ### Step 5: Analyzing the Equation Since \(1000 \times ijk\) is divisible by \(1000\), \(pqr(pqr - 1)\) must also be divisible by \(1000\). This means that \(pqr\) must be such that the product \(pqr(pqr - 1)\) is a multiple of \(1000\). ### Step 6: Finding Suitable Values for \(pqr\) To satisfy the divisibility condition, \(pqr\) must end in \(0\) (so that \(pqr\) is divisible by \(10\)) or \(pqr - 1\) must end in \(0\) (so that \(pqr - 1\) is divisible by \(10\)). ### Step 7: Testing Values Let's test some values of \(pqr\): 1. If \(pqr = 100\): \[ (100)^2 = 10000 \quad \text{(not a six-digit number)} \] 2. If \(pqr = 316\): \[ (316)^2 = 99856 \quad \text{(not a six-digit number)} \] 3. If \(pqr = 320\): \[ (320)^2 = 102400 \quad \text{(valid)} \] Here, \(ijk = 102\) and \(pqr = 400\). ### Step 8: Calculate \(i \times j \times k \times p \times q \times r\) From \(ijk = 102\) and \(pqr = 400\): - \(i = 1\), \(j = 0\), \(k = 2\), \(p = 4\), \(q = 0\), \(r = 0\). Calculating the product: \[ i \times j \times k \times p \times q \times r = 1 \times 0 \times 2 \times 4 \times 0 \times 0 = 0 \] ### Final Answer The value of \(i \times j \times k \times p \times q \times r\) is \(0\).
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