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The sum of all the factors of 45000 whic...

The sum of all the factors of 45000 which are exactly the multiples of 10 is :

A

152295

B

141960

C

600

D

None of these

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The correct Answer is:
To find the sum of all the factors of 45000 that are exactly multiples of 10, we can follow these steps: ### Step 1: Prime Factorization of 45000 First, we need to find the prime factorization of 45000. 45000 can be broken down as follows: - 45000 = 450 × 100 - 450 = 45 × 10 = (5 × 9) × (2 × 5) = (5 × 3 × 3) × (2 × 5) - 100 = 10 × 10 = (2 × 5) × (2 × 5) = 2² × 5² So, combining these, we have: - 45000 = 5² × (3²) × (2 × 5) × (2² × 5²) - This simplifies to: 45000 = 2³ × 3² × 5⁴ ### Step 2: Identify Factors that are Multiples of 10 Next, we need to find the factors of 45000 that are multiples of 10. A number is a multiple of 10 if it includes at least one factor of 2 and one factor of 5. From the prime factorization: - The factors of 10 can be expressed as: 10 = 2¹ × 5¹ ### Step 3: Determine the Range of Exponents for Factors To find the factors of 45000 that are multiples of 10, we can express them in the form: - \(2^a × 3^b × 5^c\) where: - \(a \geq 1\) (since we need at least one factor of 2) - \(b\) can be 0, 1, or 2 (since the maximum exponent of 3 is 2) - \(c \geq 1\) and can go up to 4 (since the maximum exponent of 5 is 4) ### Step 4: Calculate the Sum of the Factors Using the formula for the sum of the factors, we can calculate it as follows: The sum of the factors of a number in the form \(p^n\) is given by: \[ \text{Sum} = \frac{p^{n+1} - 1}{p - 1} \] For our case: 1. For \(2^a\) where \(a = 1, 2, 3\): \[ \text{Sum} = 2^1 + 2^2 + 2^3 = 2 + 4 + 8 = 14 \] 2. For \(3^b\) where \(b = 0, 1, 2\): \[ \text{Sum} = 3^0 + 3^1 + 3^2 = 1 + 3 + 9 = 13 \] 3. For \(5^c\) where \(c = 1, 2, 3, 4\): \[ \text{Sum} = 5^1 + 5^2 + 5^3 + 5^4 = 5 + 25 + 125 + 625 = 780 \] ### Step 5: Combine the Sums Now, we multiply the sums together: \[ \text{Total Sum} = 14 × 13 × 780 \] Calculating this: 1. \(14 × 13 = 182\) 2. \(182 × 780 = 141960\) ### Final Answer Thus, the sum of all the factors of 45000 that are exactly multiples of 10 is **141960**. ---
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