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A man sells chocolate which are in the b...

A man sells chocolate which are in the boxes. Only either full box or half a box of chocolate can be purchased from him. A customer comes and buys half the number of boxes which the seller had plus half a box more. A second customer comes and purchases half the remaining number of boxes plus half a box. After this the seller is left with no chocolate boxes. How many chocolate boxes the seller had initially ?

A

2

B

3

C

4

D

3.5

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's denote the initial number of boxes the seller had as \( x \). ### Step 1: First Customer's Purchase The first customer buys half the number of boxes the seller had plus half a box more. This can be expressed mathematically as: \[ \text{Boxes bought by first customer} = \frac{x}{2} + \frac{1}{2} \] After this purchase, the number of boxes left with the seller becomes: \[ \text{Remaining boxes} = x - \left(\frac{x}{2} + \frac{1}{2}\right) = x - \frac{x}{2} - \frac{1}{2} = \frac{x}{2} - \frac{1}{2} \] ### Step 2: Second Customer's Purchase The second customer then comes and buys half of the remaining boxes plus half a box. The remaining boxes after the first customer is \( \frac{x}{2} - \frac{1}{2} \). The second customer buys: \[ \text{Boxes bought by second customer} = \frac{1}{2} \left(\frac{x}{2} - \frac{1}{2}\right) + \frac{1}{2} \] Calculating this: \[ = \frac{x}{4} - \frac{1}{4} + \frac{1}{2} = \frac{x}{4} - \frac{1}{4} + \frac{2}{4} = \frac{x}{4} + \frac{1}{4} \] After this purchase, the number of boxes left with the seller becomes: \[ \text{Remaining boxes} = \left(\frac{x}{2} - \frac{1}{2}\right) - \left(\frac{x}{4} + \frac{1}{4}\right) \] Calculating this: \[ = \frac{x}{2} - \frac{1}{2} - \frac{x}{4} - \frac{1}{4} = \frac{2x}{4} - \frac{x}{4} - \frac{2}{4} - \frac{1}{4} = \frac{x}{4} - \frac{3}{4} \] ### Step 3: Setting the Equation According to the problem, after both customers, the seller is left with no boxes: \[ \frac{x}{4} - \frac{3}{4} = 0 \] Solving for \( x \): \[ \frac{x}{4} = \frac{3}{4} \] Multiplying both sides by 4: \[ x = 3 \] ### Conclusion The seller initially had **3 boxes** of chocolates.
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