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How many integer values of x and y satisfy the expression 4x + 7y = 3 where |x|<1000 and |y| < 1000?.

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To solve the equation \(4x + 7y = 3\) for integer values of \(x\) and \(y\) under the constraints \(|x| < 1000\) and \(|y| < 1000\), we can follow these steps: ### Step 1: Rearranging the Equation We start with the equation: \[ 4x + 7y = 3 \] We can express \(y\) in terms of \(x\): \[ 7y = 3 - 4x \quad \Rightarrow \quad y = \frac{3 - 4x}{7} \] ### Step 2: Finding Integer Solutions For \(y\) to be an integer, the numerator \(3 - 4x\) must be divisible by \(7\). This means: \[ 3 - 4x \equiv 0 \mod{7} \] Rearranging gives: \[ 4x \equiv 3 \mod{7} \] ### Step 3: Solving the Modular Equation To solve \(4x \equiv 3 \mod{7}\), we can find the multiplicative inverse of \(4\) modulo \(7\). The inverse is \(2\) because: \[ 4 \cdot 2 \equiv 1 \mod{7} \] Multiplying both sides of the equation \(4x \equiv 3\) by \(2\): \[ x \equiv 6 \mod{7} \] This means: \[ x = 6 + 7k \quad \text{for some integer } k \] ### Step 4: Substituting Back to Find \(y\) Substituting \(x = 6 + 7k\) back into the equation for \(y\): \[ y = \frac{3 - 4(6 + 7k)}{7} = \frac{3 - 24 - 28k}{7} = \frac{-21 - 28k}{7} = -3 - 4k \] Thus, we have: \[ x = 6 + 7k \quad \text{and} \quad y = -3 - 4k \] ### Step 5: Applying the Constraints Now we need to apply the constraints \(|x| < 1000\) and \(|y| < 1000\). 1. For \(|x| < 1000\): \[ -1000 < 6 + 7k < 1000 \] This simplifies to: \[ -1006 < 7k < 994 \quad \Rightarrow \quad -144.857 < k < 142 \] Thus, \(k\) can take integer values from \(-144\) to \(142\). 2. For \(|y| < 1000\): \[ -1000 < -3 - 4k < 1000 \] This simplifies to: \[ -997 < -4k < 1003 \quad \Rightarrow \quad -250.75 < k < -250.75 \] Thus, \(k\) can take integer values from \(-250\) to \(249\). ### Step 6: Finding the Range of \(k\) The valid integer values of \(k\) must satisfy both constraints. The overlapping range from \(-144\) to \(142\) gives: - Minimum \(k = -143\) - Maximum \(k = 142\) ### Step 7: Counting the Integer Values The total number of integer values for \(k\) is: \[ 142 - (-143) + 1 = 142 + 143 + 1 = 286 \] ### Final Answer Thus, the total number of integer solutions \((x, y)\) that satisfy the equation under the given constraints is: \[ \boxed{286} \]
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ARIHANT SSC-FUNDAMENTALS -FINAL ROUND
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