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The 44th terms of the following sequence...

The 44th terms of the following sequence `1,2,3,10,11,12,13,20,21,22,23,30,31,….` is :

A

1331

B

17776

C

12330

D

13330

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The correct Answer is:
To find the 44th term of the sequence `1, 2, 3, 10, 11, 12, 13, 20, 21, 22, 23, 30, 31, ...`, we can analyze the pattern of the sequence step by step. ### Step-by-Step Solution: 1. **Identify the Pattern**: The sequence consists of numbers that can be grouped based on their tens place. The numbers are: - From 1 to 3: `1, 2, 3` - From 10 to 13: `10, 11, 12, 13` - From 20 to 23: `20, 21, 22, 23` - From 30 to 33: `30, 31, 32, 33` - And so on... 2. **Count the Terms**: - The first group (1 to 3) has 3 terms. - The second group (10 to 13) has 4 terms. - The third group (20 to 23) has 4 terms. - The fourth group (30 to 33) has 4 terms. - Continuing this pattern, we can see that every group starting from 10 contributes 4 terms. 3. **Calculate the Total Terms**: - The first group contributes 3 terms. - The next groups (10s, 20s, 30s, etc.) contribute 4 terms each. - To find out how many complete groups we have until we reach the 44th term, we can calculate: - 3 (from the first group) + 4n (from the subsequent groups) = 44 - 4n = 44 - 3 - 4n = 41 - n = 41 / 4 = 10.25 This means we have 10 complete groups of 4 terms from the 10s onwards. 4. **Determine the Group of the 44th Term**: - The first group contributes 3 terms. - The next 10 groups contribute 40 terms (10 groups × 4 terms each). - Therefore, the 43rd term is the last term of the 10th group (which is 30 to 33). - The 44th term will be the first term of the next group, which is the 11th group (40 to 43). 5. **Find the 44th Term**: - The first term of the 11th group (40s) is `40`. Thus, the 44th term of the sequence is **40**.
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