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Find a fraction which shall bear the sam...

Find a fraction which shall bear the same ratio to 1/27 that 3/5 does to 3/40.

A

5/27

B

13/27

C

8/27

D

can't be determined

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to find a fraction \( \frac{x}{y} \) that has the same ratio to \( \frac{1}{27} \) as \( \frac{3}{5} \) has to \( \frac{3}{40} \). ### Step-by-Step Solution: 1. **Set Up the Ratios**: We start with the equation that represents the problem: \[ \frac{x}{y} : \frac{1}{27} = \frac{3}{5} : \frac{3}{40} \] 2. **Cross-Multiply to Form an Equation**: From the ratio, we can write: \[ \frac{x}{y} = \frac{3/5}{3/40} \] To simplify this, we can cross-multiply: \[ \frac{x}{y} = \frac{3}{5} \times \frac{40}{3} \] 3. **Simplify the Right Side**: Notice that the \( 3 \) in the numerator and denominator cancels out: \[ \frac{x}{y} = \frac{40}{5} \] Now simplify \( \frac{40}{5} \): \[ \frac{x}{y} = 8 \] 4. **Express as a Fraction**: We can express this as: \[ \frac{x}{y} = \frac{8}{1} \] 5. **Find the Fraction Relative to \( \frac{1}{27} \)**: Now, we need to relate this back to \( \frac{1}{27} \): \[ \frac{x}{y} = 8 \cdot \frac{1}{27} = \frac{8}{27} \] Thus, the fraction that bears the same ratio to \( \frac{1}{27} \) as \( \frac{3}{5} \) does to \( \frac{3}{40} \) is: \[ \frac{8}{27} \] ### Final Answer: The required fraction is \( \frac{8}{27} \).
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