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The average of 9 numbers is 11. If each ...

The average of 9 numbers is 11. If each of these 9 numbers is multiplied by 5 and then 5 is added to each of these resultant numbers, then the new average is :

A

20

B

30

C

60

D

50

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the new average after performing the operations on the original numbers. ### Step 1: Calculate the total sum of the original numbers Given that the average of 9 numbers is 11, we can find the total sum of these numbers. \[ \text{Total Sum} = \text{Average} \times \text{Number of elements} = 11 \times 9 = 99 \] **Hint:** Remember that the sum of the numbers can be calculated by multiplying the average by the number of elements. ### Step 2: Apply the operations to each number Each of the 9 numbers is multiplied by 5 and then 5 is added to each resultant number. If we denote the original numbers as \( x_1, x_2, \ldots, x_9 \), the new numbers will be: \[ \text{New Number} = 5x_i + 5 \quad \text{for each } i = 1, 2, \ldots, 9 \] ### Step 3: Calculate the new total sum Now, we can express the total sum of the new numbers: \[ \text{New Total Sum} = (5x_1 + 5) + (5x_2 + 5) + \ldots + (5x_9 + 5) \] This can be simplified as: \[ \text{New Total Sum} = 5(x_1 + x_2 + \ldots + x_9) + 5 \times 9 \] Substituting the total sum we calculated in Step 1: \[ \text{New Total Sum} = 5(99) + 45 = 495 + 45 = 540 \] ### Step 4: Calculate the new average Now, we can find the new average by dividing the new total sum by the number of elements: \[ \text{New Average} = \frac{\text{New Total Sum}}{\text{Number of elements}} = \frac{540}{9} = 60 \] ### Final Answer The new average is **60**. ---
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