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I went to Delhi at a speed of 200 km/hr ...

I went to Delhi at a speed of 200 km/hr but suddenly I returned to the same place at a speed of 600 km/hr. What is my average speed :

A

300 km/hr

B

400 km/hr

C

366.66 km/hr

D

none of these

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AI Generated Solution

The correct Answer is:
To find the average speed for the entire journey, we can follow these steps: ### Step 1: Define the distance Let the distance to Delhi be \( x \) km. ### Step 2: Calculate the total distance Since the journey involves going to Delhi and returning back to the starting point, the total distance covered is: \[ \text{Total Distance} = x + x = 2x \text{ km} \] ### Step 3: Calculate the time taken for each part of the journey 1. **Time taken to go to Delhi**: - Speed = 200 km/hr - Time = Distance / Speed = \( \frac{x}{200} \) hours 2. **Time taken to return from Delhi**: - Speed = 600 km/hr - Time = Distance / Speed = \( \frac{x}{600} \) hours ### Step 4: Calculate the total time taken The total time for the entire journey is the sum of the time taken to go and the time taken to return: \[ \text{Total Time} = \frac{x}{200} + \frac{x}{600} \] ### Step 5: Find a common denominator to add the times The common denominator for 200 and 600 is 600. We can rewrite the times: \[ \frac{x}{200} = \frac{3x}{600} \] Thus, \[ \text{Total Time} = \frac{3x}{600} + \frac{x}{600} = \frac{4x}{600} = \frac{x}{150} \text{ hours} \] ### Step 6: Calculate the average speed Average speed is defined as the total distance divided by the total time: \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{2x}{\frac{x}{150}} = 2x \times \frac{150}{x} \] Here, \( x \) cancels out: \[ \text{Average Speed} = 2 \times 150 = 300 \text{ km/hr} \] ### Conclusion Thus, the average speed for the entire journey is: \[ \text{Average Speed} = 300 \text{ km/hr} \]
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