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There are 3 sets of natural numbers 1 ot...

There are 3 sets of natural numbers 1 ot 100. Set A contains all the natural numbers which are prime, upto 100. Set B contains all the non-prime even natural numbers upto 100. Set C contains all the non-prime odd natural numbers upto 100 i.e.,
A = {2,3,5,7,11,...89, 97}
B = {4,6,8,10,12,...98,100}
C = {1,9,15,21,25,27,33,95,99}
The average of the Set C is :

A

52

B

49.87

C

55.46

D

can't be determined

Text Solution

AI Generated Solution

The correct Answer is:
To find the average of Set C, we will follow these steps: ### Step 1: Identify the elements of Set C Set C contains all the non-prime odd natural numbers up to 100. The elements of Set C are: C = {1, 9, 15, 21, 25, 27, 33, 35, 45, 49, 51, 55, 57, 63, 65, 69, 77, 81, 85, 87, 91, 93, 95, 99} ### Step 2: Count the number of elements in Set C Now, we need to count how many elements are in Set C. - The elements are: 1, 9, 15, 21, 25, 27, 33, 35, 45, 49, 51, 55, 57, 63, 65, 69, 77, 81, 85, 87, 91, 93, 95, 99 - There are 24 elements in total. ### Step 3: Calculate the sum of the elements in Set C Next, we will sum all the elements in Set C: Sum = 1 + 9 + 15 + 21 + 25 + 27 + 33 + 35 + 45 + 49 + 51 + 55 + 57 + 63 + 65 + 69 + 77 + 81 + 85 + 87 + 91 + 93 + 95 + 99 Calculating the sum: - 1 + 9 = 10 - 10 + 15 = 25 - 25 + 21 = 46 - 46 + 25 = 71 - 71 + 27 = 98 - 98 + 33 = 131 - 131 + 35 = 166 - 166 + 45 = 211 - 211 + 49 = 260 - 260 + 51 = 311 - 311 + 55 = 366 - 366 + 57 = 423 - 423 + 63 = 486 - 486 + 65 = 551 - 551 + 69 = 620 - 620 + 77 = 697 - 697 + 81 = 778 - 778 + 85 = 863 - 863 + 87 = 950 - 950 + 91 = 1041 - 1041 + 93 = 1134 - 1134 + 95 = 1229 - 1229 + 99 = 1328 So, the sum of Set C is 1328. ### Step 4: Calculate the average of Set C The average is calculated by dividing the sum by the number of elements: Average = Sum of elements / Number of elements Average = 1328 / 24 Calculating the average: Average = 55.33 (approximately) ### Final Answer The average of Set C is approximately 55.33. ---
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There are 3 sets of natural numbers 1 ot 100. Set A contains all the natural numbers which are prime, upto 100. Set B contains all the non-prime even natural numbers upto 100. Set C contains all the non-prime odd natural numbers upto 100 i.e., A = {2,3,5,7,11,...89, 97} B = {4,6,8,10,12,...98,100} C = {1,9,15,21,25,27,33,95,99} The average of all the elements of B is :

ARIHANT SSC-AVERAGES-Final Round
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