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There are 3 sets of natural numbers 1 ot...

There are 3 sets of natural numbers 1 ot 100. Set A contains all the natural numbers which are prime, upto 100. Set B contains all the non-prime even natural numbers upto 100. Set C contains all the non-prime odd natural numbers upto 100 i.e.,
A = {2,3,5,7,11,...89, 97}
B = {4,6,8,10,12,...98,100}
C = {1,9,15,21,25,27,33,95,99}
If a least and a greatest element of Set C are transferred from Set C to Set A then the average of Set A :

A

a. increases

B

b. decreases

C

c. remains constant

D

d. can't be determined

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these instructions: ### Step 1: Identify the sets - **Set A**: Contains all prime numbers up to 100. - **Set B**: Contains all non-prime even natural numbers up to 100. - **Set C**: Contains all non-prime odd natural numbers up to 100. ### Step 2: List the elements of Set A The prime numbers up to 100 are: \[ A = \{2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97\} \] Count of elements in Set A = 25. ### Step 3: List the elements of Set C The non-prime odd natural numbers up to 100 are: \[ C = \{1, 9, 15, 21, 25, 27, 33, 35, 39, 45, 49, 51, 55, 57, 63, 65, 69, 77, 81, 85, 87, 91, 93, 95, 99\} \] Count of elements in Set C = 25. ### Step 4: Identify the least and greatest elements of Set C - Least element of Set C = 1 - Greatest element of Set C = 99 ### Step 5: Transfer the least and greatest elements from Set C to Set A After transferring: - New Set A = \( A \cup \{1, 99\} \) - New Set A = \( \{1, 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 99\} \) ### Step 6: Count the new number of elements in Set A New count of elements in Set A = 27 (25 original + 2 transferred). ### Step 7: Calculate the sum of the original elements in Set A The sum of the original prime numbers in Set A is: \[ \text{Sum of Set A} = 1060 \] ### Step 8: Calculate the new sum of Set A after transferring elements New sum of Set A = Original sum + Least element + Greatest element \[ \text{New Sum} = 1060 + 1 + 99 = 1160 \] ### Step 9: Calculate the average of the new Set A Average of Set A = New Sum / New Count of Elements \[ \text{Average} = \frac{1160}{27} \approx 42.96 \] ### Conclusion The average of Set A after transferring the least and greatest elements from Set C is approximately 42.96. ---
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There are 3 sets of natural numbers 1 ot 100. Set A contains all the natural numbers which are prime, upto 100. Set B contains all the non-prime even natural numbers upto 100. Set C contains all the non-prime odd natural numbers upto 100 i.e., A = {2,3,5,7,11,...89, 97} B = {4,6,8,10,12,...98,100} C = {1,9,15,21,25,27,33,95,99} The average of all the elements of B is :

A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...98,100} C={3,9,15,21,27,33...,99} If a least and a greatest element of Set C are transferred from Set C to Set A then the average of Set A :

ARIHANT SSC-AVERAGES-Final Round
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