A milkman has two types of milk. In the first container the percentage of milk is 80% and in the second container the percentage of milk is 60%. If he mixes 28 litres of milk of the first container to the 32 litres of milk of the second container, then the percentage of milk in the mixture is :

Options

A. 63.99
B. 69.33
C. 72.5
D. 75.2

Answer

To find the percentage of milk in the mixture when the milkman mixes milk from two containers, we can follow these steps:

### Step 1: Identify the quantities and percentages of milk in each container.
- First container: 80% milk
- Second container: 60% milk
- Quantity from the first container: 28 liters
- Quantity from the second container: 32 liters

### Step 2: Calculate the total quantity of milk from each container.
- Milk from the first container = 28 liters * 80% = 28 * 0.80 = 22.4 liters
- Milk from the second container = 32 liters * 60% = 32 * 0.60 = 19.2 liters

### Step 3: Calculate the total quantity of milk in the mixture.
- Total milk in the mixture = Milk from the first container + Milk from the second container
- Total milk in the mixture = 22.4 liters + 19.2 liters = 41.6 liters

### Step 4: Calculate the total volume of the mixture.
- Total volume of the mixture = Quantity from the first container + Quantity from the second container
- Total volume of the mixture = 28 liters + 32 liters = 60 liters

### Step 5: Calculate the percentage of milk in the mixture.
- Percentage of milk in the mixture = (Total milk in the mixture / Total volume of the mixture) * 100
- Percentage of milk in the mixture = (41.6 liters / 60 liters) * 100 = 69.33%

### Final Answer:
The percentage of milk in the mixture is **69.33%**.

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