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From the 50 litres of milk, 5 litres of ...

From the 50 litres of milk, 5 litres of milk is taken out and after it 5 litres of water is added to the rest amount of milk. Again 5 litres of mixture of milk and water is drawn out and it was replaced by 5 litres of water. If this process is continued similarly for the third time, the amount of milk left after the third replacement :

A

45 L

B

36.45 L

C

40.5 L

D

42.5 L

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The correct Answer is:
To solve the problem step by step, we can follow these calculations: ### Step 1: Initial Setup We start with 50 liters of pure milk. ### Step 2: First Replacement - We take out 5 liters of milk. - Remaining milk = 50 liters - 5 liters = 45 liters. - We then add 5 liters of water. - Total mixture now = 45 liters of milk + 5 liters of water = 50 liters of mixture. ### Step 3: Calculate Milk Concentration After First Replacement - The concentration of milk after the first replacement is: \[ \text{Concentration of milk} = \frac{\text{Remaining milk}}{\text{Total mixture}} = \frac{45}{50} = 0.9 \] ### Step 4: Second Replacement - Now we take out 5 liters of this mixture (which is 90% milk and 10% water). - Amount of milk taken out = 5 liters × 0.9 = 4.5 liters. - Amount of water taken out = 5 liters × 0.1 = 0.5 liters. - Remaining milk after second replacement = 45 liters - 4.5 liters = 40.5 liters. - We add 5 liters of water again. - Total mixture now = 40.5 liters of milk + 5 liters of water = 45.5 liters of mixture. ### Step 5: Calculate Milk Concentration After Second Replacement - The concentration of milk after the second replacement is: \[ \text{Concentration of milk} = \frac{40.5}{50} = 0.81 \] ### Step 6: Third Replacement - Again, we take out 5 liters of this mixture (which is 81% milk and 19% water). - Amount of milk taken out = 5 liters × 0.81 = 4.05 liters. - Amount of water taken out = 5 liters × 0.19 = 0.95 liters. - Remaining milk after third replacement = 40.5 liters - 4.05 liters = 36.45 liters. - We add 5 liters of water again. - Total mixture now = 36.45 liters of milk + 5 liters of water = 41.45 liters of mixture. ### Step 7: Final Calculation of Milk Left After performing the operation three times, the amount of milk left is: \[ \text{Amount of milk left} = 36.45 \text{ liters} \] ### Summary The amount of milk left after the third replacement is **36.45 liters**. ---
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