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Three boys are aged 2 years, 4 years and...

Three boys are aged 2 years, 4 years and 8 years.
They went to divide seventy rupees in the ratio of their ages. How much money would each get?

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To solve the problem of dividing 70 rupees among three boys aged 2 years, 4 years, and 8 years in the ratio of their ages, we can follow these steps: ### Step 1: Identify the Ages The ages of the three boys are: - First boy: 2 years - Second boy: 4 years - Third boy: 8 years ### Step 2: Write the Ratio of Their Ages The ratio of their ages can be expressed as: - Ratio = 2 : 4 : 8 ### Step 3: Simplify the Ratio To simplify the ratio, we can divide each term by the smallest age (which is 2): - Simplified Ratio = 1 : 2 : 4 ### Step 4: Calculate the Total Parts of the Ratio Now, we need to find the total number of parts in the ratio: - Total parts = 1 + 2 + 4 = 7 parts ### Step 5: Determine the Value of Each Part Next, we can find the value of each part by dividing the total amount of money (70 rupees) by the total number of parts: - Value of each part = Total Money / Total Parts = 70 / 7 = 10 rupees ### Step 6: Calculate Each Boy's Share Now we can calculate how much money each boy gets based on the simplified ratio: - First boy's share = 1 part = 1 * 10 = 10 rupees - Second boy's share = 2 parts = 2 * 10 = 20 rupees - Third boy's share = 4 parts = 4 * 10 = 40 rupees ### Step 7: Verify the Total Amount Finally, we can verify that the total amount distributed adds up to 70 rupees: - Total = 10 + 20 + 40 = 70 rupees ### Final Shares: - First boy: 10 rupees - Second boy: 20 rupees - Third boy: 40 rupees ---
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