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The mean proportional between 8 and 97 i...

The mean proportional between 8 and 97 is:

A

16

B

53

C

112

D

28

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The correct Answer is:
To find the mean proportional between 8 and 97, we can follow these steps: ### Step 1: Understand the concept of mean proportional The mean proportional \( A \) between two numbers \( a \) and \( b \) is defined such that the ratio \( \frac{a}{A} = \frac{A}{b} \). This means that \( A \) is the geometric mean of \( a \) and \( b \). ### Step 2: Set up the equation For our specific values, we have: - \( a = 8 \) - \( b = 97 \) Thus, we can write the equation: \[ \frac{8}{A} = \frac{A}{97} \] ### Step 3: Cross-multiply to eliminate the fractions Cross-multiplying gives us: \[ 8 \cdot 97 = A \cdot A \] This simplifies to: \[ 8 \times 97 = A^2 \] ### Step 4: Calculate \( 8 \times 97 \) Now, we calculate \( 8 \times 97 \): \[ 8 \times 97 = 776 \] So, we have: \[ A^2 = 776 \] ### Step 5: Solve for \( A \) To find \( A \), we take the square root of both sides: \[ A = \sqrt{776} \] ### Step 6: Calculate \( \sqrt{776} \) Now we can calculate \( \sqrt{776} \). Approximating this gives: \[ \sqrt{776} \approx 27.856 \] For practical purposes, we can round this to: \[ A \approx 28 \] ### Conclusion Thus, the mean proportional between 8 and 97 is approximately \( 28 \). ---
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ARIHANT SSC-RATIO, PROPORTION & VARIATION-FINAL ROUND
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