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Radhika purchased one dozen bangles. One...

Radhika purchased one dozen bangles. One day she slipped on the floor fell down. What can not be the ratio of broken is unbroken bangle:

A

`1:2`

B

`1:3`

C

`2:3`

D

`1:5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine which ratio of broken to unbroken bangles is not possible given that Radhika purchased one dozen (12) bangles. ### Step-by-Step Solution: 1. **Understanding the Total Bangles**: Radhika purchased 12 bangles in total. 2. **Defining the Ratios**: We will analyze the four options provided to see which one does not represent a possible scenario of broken to unbroken bangles. 3. **Option 1: Ratio 1:2** - Total parts = 1 + 2 = 3 - Each part represents \( \frac{12}{3} = 4 \) bangles. - Broken bangles = 1 part = 4 bangles. - Unbroken bangles = 2 parts = \( 2 \times 4 = 8 \) bangles. - This ratio is possible (4 broken, 8 unbroken). 4. **Option 2: Ratio 1:3** - Total parts = 1 + 3 = 4 - Each part represents \( \frac{12}{4} = 3 \) bangles. - Broken bangles = 1 part = 3 bangles. - Unbroken bangles = 3 parts = \( 3 \times 3 = 9 \) bangles. - This ratio is also possible (3 broken, 9 unbroken). 5. **Option 3: Ratio 2:3** - Total parts = 2 + 3 = 5 - Each part represents \( \frac{12}{5} = 2.4 \) bangles. - Broken bangles = 2 parts = \( 2 \times 2.4 = 4.8 \) bangles. - Unbroken bangles = 3 parts = \( 3 \times 2.4 = 7.2 \) bangles. - This ratio is not possible since we cannot have a fraction of a bangle. 6. **Option 4: Ratio 1:5** - Total parts = 1 + 5 = 6 - Each part represents \( \frac{12}{6} = 2 \) bangles. - Broken bangles = 1 part = 2 bangles. - Unbroken bangles = 5 parts = \( 5 \times 2 = 10 \) bangles. - This ratio is possible (2 broken, 10 unbroken). 7. **Conclusion**: The ratio that cannot represent broken to unbroken bangles is **Option 3: 2:3**.
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