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Find the 22nd term of the G.P. -2,2,-2,…...

Find the 22nd term of the G.P. -2,2,-2,… :

A

`-22`

B

`-2`

C

2

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the 22nd term of the given geometric progression (G.P.) -2, 2, -2, ..., we can follow these steps: ### Step 1: Identify the first term (A) and the common ratio (R) The first term \( A \) of the G.P. is: \[ A = -2 \] To find the common ratio \( R \), we can divide the second term by the first term: \[ R = \frac{T_2}{T_1} = \frac{2}{-2} = -1 \] ### Step 2: Use the formula for the n-th term of a G.P. The formula for the n-th term \( T_n \) of a G.P. is given by: \[ T_n = A \cdot R^{(n-1)} \] ### Step 3: Substitute the values into the formula We want to find the 22nd term, so we set \( n = 22 \): \[ T_{22} = A \cdot R^{(22-1)} \] \[ T_{22} = -2 \cdot (-1)^{21} \] ### Step 4: Calculate \( (-1)^{21} \) Since 21 is an odd number, we have: \[ (-1)^{21} = -1 \] ### Step 5: Substitute back to find \( T_{22} \) Now substituting this value back into the equation: \[ T_{22} = -2 \cdot (-1) \] \[ T_{22} = 2 \] ### Final Answer The 22nd term of the G.P. is: \[ T_{22} = 2 \] ---
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Knowledge Check

  • Find the 15th term of the G.P -2,2,-2,….

    A
    -22
    B
    2
    C
    -2
    D
    none of these
  • The fourth term of the G.P. 4, - 2 , 1 , … is

    A
    `(-1)/(2)`
    B
    `(1)/(2)`
    C
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    D
    `(1)/(4)`
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