Home
Class 14
MATHS
Ratio between heights of two cylinder in...

Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find the ratio between their radius.

A

a. 2:3

B

b. 3:2

C

c. 3:4

D

d. 4:3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the radii of two cylinders given the ratio of their heights and volumes. ### Step-by-Step Solution: 1. **Understand the Given Ratios:** - The ratio of the heights of the two cylinders is given as \( h_1 : h_2 = 3 : 5 \). - The ratio of the volumes of the two cylinders is given as \( V_1 : V_2 = 27 : 80 \). 2. **Volume of a Cylinder Formula:** - The volume \( V \) of a cylinder is calculated using the formula: \[ V = \pi r^2 h \] - For Cylinder 1, let the radius be \( r_1 \) and height be \( h_1 \). - For Cylinder 2, let the radius be \( r_2 \) and height be \( h_2 \). 3. **Set Up the Volume Ratio:** - Using the volume formula, we can express the volumes of the two cylinders: \[ V_1 = \pi r_1^2 h_1 \quad \text{and} \quad V_2 = \pi r_2^2 h_2 \] - The ratio of the volumes can be written as: \[ \frac{V_1}{V_2} = \frac{\pi r_1^2 h_1}{\pi r_2^2 h_2} \] - This simplifies to: \[ \frac{V_1}{V_2} = \frac{r_1^2 h_1}{r_2^2 h_2} \] 4. **Substitute the Given Ratios:** - We know \( \frac{V_1}{V_2} = \frac{27}{80} \) and the height ratio \( \frac{h_1}{h_2} = \frac{3}{5} \). - Substitute \( h_1 = 3k \) and \( h_2 = 5k \) for some \( k \): \[ \frac{27}{80} = \frac{r_1^2 \cdot 3k}{r_2^2 \cdot 5k} \] - The \( k \) cancels out: \[ \frac{27}{80} = \frac{3r_1^2}{5r_2^2} \] 5. **Cross Multiply to Solve for Radii:** - Cross multiplying gives: \[ 27 \cdot 5 r_2^2 = 80 \cdot 3 r_1^2 \] - Simplifying this: \[ 135 r_2^2 = 240 r_1^2 \] 6. **Rearranging for the Ratio of Radii:** - Dividing both sides by \( r_1^2 r_2^2 \): \[ \frac{r_1^2}{r_2^2} = \frac{135}{240} \] - Simplifying \( \frac{135}{240} \): \[ \frac{135 \div 15}{240 \div 15} = \frac{9}{16} \] 7. **Taking the Square Root:** - To find the ratio of the radii, take the square root: \[ \frac{r_1}{r_2} = \sqrt{\frac{9}{16}} = \frac{3}{4} \] 8. **Final Ratio:** - Thus, the ratio of the radii of the two cylinders is: \[ r_1 : r_2 = 3 : 4 \] ### Conclusion: The ratio between the radii of the two cylinders is \( 3 : 4 \).
Promotional Banner

Topper's Solved these Questions

  • SEQUENCE, SERIES & PROGRESSIONS

    ARIHANT SSC|Exercise EXERCISE LEVEL-2|47 Videos
  • SEQUENCE, SERIES & PROGRESSIONS

    ARIHANT SSC|Exercise Final Round|18 Videos
  • SEQUENCE, SERIES & PROGRESSIONS

    ARIHANT SSC|Exercise INTRODUCTION EXERCISE- 18.3|3 Videos
  • RATIO, PROPORTION & VARIATION

    ARIHANT SSC|Exercise FINAL ROUND|16 Videos
  • SET THEORY

    ARIHANT SSC|Exercise EXERCISE - 15 (LEVEL -1)|29 Videos

Similar Questions

Explore conceptually related problems

The radii of the bases of two cylinders are in the ratio 3:5 and their heights are in the ratio 2:3. Find the ratio of their curved surface areas.

The volume of two hemisphere are in the ratio 8:27. Find the ratio of their radii.

If the radii of two cylinders are in the ratio 2:3 and their heights are in the ratio 5:3, then find the ratio of their volumes.

The radii of two cylinders are in the ratio of 3:5 and their heights are in the ratio 4:3 . The ratio of their volumes is :

The radii of two cylinders are in the ratio 2:3 and their heights are in the ratio 5:3 . The ratio of their volumes is

The radii of 2 cylinders are in the ratio 1:2 and their heights are in the ratio 3: 4. Then, find the ratio of their volumes

The ratii of two cylinders are in the ratio 2 : 3 and their heights are in the ratio 5 : 3 . The ratio of their volumes is

The diameters of two cylinders are in the ratio 3:2 and their volumes are equal. The ratio of their heights is

ARIHANT SSC-SEQUENCE, SERIES & PROGRESSIONS-EXERCISE LEVEL-1
  1. Find the sum of the series 2sqrt3 , 2sqrt2 , 4/(sqrt3) , ….

    Text Solution

    |

  2. The number of terms in an A.P. is even , the sum of odd terms is 63 a...

    Text Solution

    |

  3. Ratio between heights of two cylinder in the ratio 3:5. Their volumes ...

    Text Solution

    |

  4. Find the sum of the three numbers in G.P. whose products is 216 and ...

    Text Solution

    |

  5. The sum of four consecutive terms in A.P. is 36 and the ratio of produ...

    Text Solution

    |

  6. The sum of four integers in A.P. is 24 and their product is 945. Find ...

    Text Solution

    |

  7. In an A.P. consisting of 23 terms , the sum of the three terms in the ...

    Text Solution

    |

  8. The sum of an infinite G.P. is 4 and the sum of their cubes is 192. Fi...

    Text Solution

    |

  9. Vibhor joined as an area manager of Quick Corporation in the pay scale...

    Text Solution

    |

  10. How many terms are common in two arithmetic progression 1,4,7,10,… upt...

    Text Solution

    |

  11. The value of 3^(1//3) . 9^(1//18) . 27^(1//81) …. ∞

    Text Solution

    |

  12. The sum of the n terms of the series 1+(1+3)+(1+3+5)+... is

    Text Solution

    |

  13. The sum of n terms of the series 1^2 + (1^2 + 3^2) + (1^2 + 3^2 + 5...

    Text Solution

    |

  14. If x, y ,z are in G.P. and a^x = b^y = c^z , then :

    Text Solution

    |

  15. The sum of integers from 113 to 113113 which are divisible by 7 is :

    Text Solution

    |

  16. The sum of n terms of a progression is 3n^2 + 5 . The number of terms ...

    Text Solution

    |

  17. If a, b, c are in A.P. and b-a, c-b, a are in G.P. then a:b:c=?

    Text Solution

    |

  18. The sum of first n terms of the series 1/2 + 3/4 + 7/8 + (15)/(16) + …...

    Text Solution

    |

  19. The sum of all two digit numbers which when divided by 4 , yield unity...

    Text Solution

    |

  20. If n arithmetic means are inserted between two quantities a and b , th...

    Text Solution

    |