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The sum of integers from 113 to 113113 w...

The sum of integers from 113 to 113113 which are divisible by 7 is :

A

a. `92358576`

B

b. `913952088`

C

c. `94501895`

D

d. `912952066`

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The correct Answer is:
To find the sum of integers from 113 to 113113 that are divisible by 7, we can follow these steps: ### Step 1: Identify the first and last terms divisible by 7 - The first integer greater than or equal to 113 that is divisible by 7 can be found by calculating \( 113 \div 7 \) and rounding up to the nearest whole number, then multiplying by 7. \[ \text{First term} = 7 \times \lceil \frac{113}{7} \rceil = 7 \times 17 = 119 \] - The last integer less than or equal to 113113 that is divisible by 7 can be found by calculating \( 113113 \div 7 \) and rounding down to the nearest whole number, then multiplying by 7. \[ \text{Last term} = 7 \times \lfloor \frac{113113}{7} \rfloor = 7 \times 16159 = 113113 \] ### Step 2: Determine the number of terms in the sequence - The numbers divisible by 7 from 119 to 113113 form an arithmetic progression (AP) where: - First term \( a = 119 \) - Last term \( l = 113113 \) - Common difference \( d = 7 \) - To find the number of terms \( n \) in the AP, we use the formula for the \( n \)-th term of an AP: \[ l = a + (n - 1) \cdot d \] Rearranging gives: \[ n = \frac{l - a}{d} + 1 \] Substituting the values: \[ n = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = \frac{113113 - 119}{7} + 1 = 16143 \] ### Step 3: Calculate the sum of the arithmetic series - The sum \( S_n \) of the first \( n \) terms of an arithmetic series can be calculated using the formula: \[ S_n = \frac{n}{2} \cdot (a + l) \] - Substituting the values we found: \[ S_{16143} = \frac{16143}{2} \cdot (119 + 113113) \] \[ S_{16143} = \frac{16143}{2} \cdot 113232 \] \[ S_{16143} = 16143 \cdot 56616 = 913952088 \] ### Final Answer The sum of integers from 113 to 113113 that are divisible by 7 is **913952088**. ---
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ARIHANT SSC-SEQUENCE, SERIES & PROGRESSIONS-EXERCISE LEVEL-1
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  3. The sum of integers from 113 to 113113 which are divisible by 7 is :

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  15. If three positive real numbers a,b,c, are in A.P. such that a*b*c=4 , ...

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  16. Three numbers form an increasing G.P. . If the middle number is double...

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