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Triangle ABC is a right angled traingle at B. If angle A= 60degree, then what is the value of Cot C?

A

a. √2

B

b. 1/√3

C

c. √3

D

d. none of these

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the Triangle We have a right-angled triangle ABC with the right angle at B. We know that angle A = 60 degrees. ### Step 2: Find Angle C In any triangle, the sum of the angles is always 180 degrees. Therefore, we can write the equation for the angles in triangle ABC as follows: \[ \text{Angle A} + \text{Angle B} + \text{Angle C} = 180^\circ \] Given: - Angle A = 60 degrees - Angle B = 90 degrees (since it is a right-angled triangle) Substituting the known values into the equation: \[ 60^\circ + 90^\circ + \text{Angle C} = 180^\circ \] ### Step 3: Solve for Angle C Now, we can solve for Angle C: \[ \text{Angle C} = 180^\circ - 60^\circ - 90^\circ \] \[ \text{Angle C} = 180^\circ - 150^\circ \] \[ \text{Angle C} = 30^\circ \] ### Step 4: Find Cotangent of Angle C We need to find the value of cotangent of angle C, which is: \[ \cot C = \cot(30^\circ) \] ### Step 5: Use the Cotangent Formula The cotangent of an angle is the reciprocal of the tangent of that angle. Therefore: \[ \cot(30^\circ) = \frac{1}{\tan(30^\circ)} \] We know that: \[ \tan(30^\circ) = \frac{1}{\sqrt{3}} \] Thus: \[ \cot(30^\circ) = \frac{1}{\frac{1}{\sqrt{3}}} = \sqrt{3} \] ### Conclusion The value of \(\cot C\) is \(\sqrt{3}\). ---
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