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how many different words can be formed w...

how many different words can be formed with the letters RAINBOW so that the vowels occupy odd places ?

A

a)676

B

b)625

C

c)343

D

d)576

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many different words can be formed with the letters of "RAINBOW" such that the vowels occupy odd places, we can follow these steps: ### Step 1: Identify the letters and their types The letters in "RAINBOW" are: - Vowels: A, I, O (3 vowels) - Consonants: R, N, B, W (4 consonants) ### Step 2: Determine the positions available The word "RAINBOW" has 7 letters, which means we have 7 positions: 1. 1st position (odd) 2. 2nd position (even) 3. 3rd position (odd) 4. 4th position (even) 5. 5th position (odd) 6. 6th position (even) 7. 7th position (odd) The odd positions are 1, 3, 5, and 7 (total of 4 odd positions). ### Step 3: Place the vowels in the odd positions We need to place the 3 vowels (A, I, O) in the 4 available odd positions. We can choose 3 positions out of the 4 for the vowels. The number of ways to choose 3 positions from 4 is given by the combination formula: \[ \text{Number of ways to choose positions} = \binom{4}{3} = 4 \] ### Step 4: Arrange the vowels Once we have chosen the 3 positions, we can arrange the 3 vowels in those positions. The number of arrangements of 3 vowels is given by: \[ \text{Arrangements of vowels} = 3! = 6 \] ### Step 5: Place the consonants in the remaining positions After placing the vowels, we have 4 consonants (R, N, B, W) that need to be placed in the remaining 4 positions (1 odd position left and 2 even positions). The number of arrangements of 4 consonants is given by: \[ \text{Arrangements of consonants} = 4! = 24 \] ### Step 6: Calculate the total arrangements Now, we multiply the number of ways to choose the vowel positions, the arrangements of the vowels, and the arrangements of the consonants: \[ \text{Total arrangements} = \binom{4}{3} \times 3! \times 4! = 4 \times 6 \times 24 \] Calculating this gives: \[ 4 \times 6 = 24 \] \[ 24 \times 24 = 576 \] ### Final Answer Thus, the total number of different words that can be formed with the letters of "RAINBOW" such that the vowels occupy odd places is **576**. ---
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ARIHANT SSC-PERMUTATIONS & COMBINATIONS -INTRODUCTORY EXERCISE -(19.1 )
  1. IF no two consonants are together then in how many ways can th...

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  2. How many words can be formed of the letters in the words RAINBO...

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  3. how many different words can be formed with the letters RAINBOW so tha...

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  4. In how many ways can the letters of the word MOBILE be so that the con...

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  5. In how many ways can the letters of the word RAINBOW be arranged...

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  6. in how many ways can the letters of the word MOBILE be arrang...

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  7. In how many ways can the letters of the word STRANGE be arranf...

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  8. Four men and three women are to be seated for a dinner such tha...

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  9. 5 men and 4 women are to be seated in a row so that the women ...

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  10. In how many ways 6 students and 4 teachers be arraged in a ro...

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  11. In how many ways can 5 girls and 3 boys stand in a row so th...

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  12. In how many different ways can 8 examination papers be arranged...

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  13. A and B undertake to do a piece of work for rs. 600. A can do it in 10...

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  14. In how many ways three different rings can be worn in four fingers wit...

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  15. How many different signals can be given using any number of flags from...

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  16. A person has 3 shirts 4 coats and 6 ties. In how many ways can he wear...

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  17. Four friends have 7 shirts, 6 paints and 8 ties. In how many ways can ...

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  18. In how many ways can 7 soldiers stand in a queue?

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  19. In how many ways can 10 soldiers stand in two rows having 5 soldiers i...

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  20. How many different signals can be made by taking 3 different coloured ...

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