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Four friends have 7 shirts, 6 paints and...

Four friends have 7 shirts, 6 paints and 8 ties. In how many ways can they wear them?

A

A. 336000

B

B. 33600

C

C. 12480

D

D. 508032000

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The correct Answer is:
To solve the problem of how many ways four friends can wear 7 shirts, 6 pants, and 8 ties, we will use the concept of permutations. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have 4 friends and they can choose from 7 shirts, 6 pants, and 8 ties. We need to find out how many different combinations of outfits they can wear. 2. **Calculating the Permutations for Shirts**: - The number of ways to choose and arrange 4 shirts from 7 shirts is given by the permutation formula \( nPr = \frac{n!}{(n-r)!} \). - Here, \( n = 7 \) and \( r = 4 \). - So, \( 7P4 = \frac{7!}{(7-4)!} = \frac{7!}{3!} = \frac{7 \times 6 \times 5 \times 4}{1} = 840 \). 3. **Calculating the Permutations for Pants**: - The number of ways to choose and arrange 4 pants from 6 pants is similarly calculated. - Here, \( n = 6 \) and \( r = 4 \). - So, \( 6P4 = \frac{6!}{(6-4)!} = \frac{6!}{2!} = \frac{6 \times 5 \times 4 \times 3}{1} = 360 \). 4. **Calculating the Permutations for Ties**: - The number of ways to choose and arrange 4 ties from 8 ties is calculated in the same manner. - Here, \( n = 8 \) and \( r = 4 \). - So, \( 8P4 = \frac{8!}{(8-4)!} = \frac{8!}{4!} = \frac{8 \times 7 \times 6 \times 5}{1} = 1680 \). 5. **Calculating the Total Combinations**: - Since the choices of shirts, pants, and ties are independent, we multiply the number of ways to choose each item. - Therefore, the total number of ways the friends can wear the outfits is: \[ \text{Total Ways} = 7P4 \times 6P4 \times 8P4 = 840 \times 360 \times 1680 \] 6. **Final Calculation**: - Now we calculate \( 840 \times 360 \times 1680 \). - First, calculate \( 840 \times 360 = 302400 \). - Then, calculate \( 302400 \times 1680 = 508032000 \). Thus, the total number of ways the four friends can wear the shirts, pants, and ties is **508032000**.
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ARIHANT SSC-PERMUTATIONS & COMBINATIONS -INTRODUCTORY EXERCISE -(19.1 )
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