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In how many ways can the letters of the ...

In how many ways can the letters of the word TAMANNA be arranged ?

A

a. 120

B

b. 420

C

c. 840

D

d. none of these

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AI Generated Solution

The correct Answer is:
To find the number of ways to arrange the letters of the word "TAMANNA", we follow these steps: ### Step 1: Count the total number of letters The word "TAMANNA" consists of 7 letters: T, A, M, A, N, N, A. ### Step 2: Identify the frequency of each letter - T appears 1 time - A appears 3 times - M appears 1 time - N appears 2 times ### Step 3: Use the formula for permutations of multiset The formula for the number of arrangements of letters in a word where some letters are repeated is given by: \[ \text{Number of arrangements} = \frac{n!}{n_1! \times n_2! \times n_3! \times \ldots} \] Where: - \( n \) is the total number of letters, - \( n_1, n_2, n_3, \ldots \) are the frequencies of the repeated letters. ### Step 4: Apply the formula In our case: - Total letters \( n = 7 \) - Frequencies: \( n_T = 1 \) (for T), \( n_A = 3 \) (for A), \( n_M = 1 \) (for M), \( n_N = 2 \) (for N) Thus, the number of arrangements is: \[ \text{Number of arrangements} = \frac{7!}{1! \times 3! \times 1! \times 2!} \] ### Step 5: Calculate the factorials Now we calculate the factorials: - \( 7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040 \) - \( 1! = 1 \) - \( 3! = 3 \times 2 \times 1 = 6 \) - \( 2! = 2 \times 1 = 2 \) ### Step 6: Substitute the values into the formula Now substitute the values into the formula: \[ \text{Number of arrangements} = \frac{5040}{1 \times 6 \times 1 \times 2} = \frac{5040}{12} = 420 \] ### Step 7: Conclusion Therefore, the total number of ways to arrange the letters of the word "TAMANNA" is **420**. ---
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ARIHANT SSC-PERMUTATIONS & COMBINATIONS -INTRODUCTORY EXERCISE -(19.2 )
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