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A man has 12 friends of whom 8 are relat...

A man has 12 friends of whom 8 are relatives.How many ways he can invite 7 friends such that 5 of them are relatives is

A

a. 336

B

b. 330

C

c. 202

D

d. 127

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The correct Answer is:
To solve the problem of how many ways a man can invite 7 friends such that 5 of them are relatives, we can follow these steps: ### Step 1: Identify the total number of friends and relatives - The man has a total of 12 friends. - Out of these, 8 are relatives and the remaining 4 are non-relatives (friends). ### Step 2: Determine the selection criteria - We need to invite a total of 7 friends. - Out of these 7 friends, 5 must be relatives. ### Step 3: Calculate the number of ways to choose the relatives - We need to select 5 relatives from the 8 available relatives. - The number of ways to choose 5 relatives from 8 is given by the combination formula \( \binom{n}{r} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. \[ \text{Number of ways to choose 5 relatives} = \binom{8}{5} \] Using the combination formula: \[ \binom{8}{5} = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 \] ### Step 4: Calculate the number of ways to choose the non-relatives - After selecting 5 relatives, we need to select 2 more friends from the remaining 4 non-relatives. - The number of ways to choose 2 non-relatives from 4 is: \[ \text{Number of ways to choose 2 non-relatives} = \binom{4}{2} \] Using the combination formula: \[ \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4!}{2!2!} = \frac{4 \times 3}{2 \times 1} = 6 \] ### Step 5: Calculate the total number of ways to invite the friends - To find the total number of ways to invite 7 friends (5 relatives and 2 non-relatives), we multiply the number of ways to choose the relatives by the number of ways to choose the non-relatives: \[ \text{Total ways} = \binom{8}{5} \times \binom{4}{2} = 56 \times 6 = 336 \] ### Final Answer Thus, the total number of ways the man can invite 7 friends such that 5 of them are relatives is **336**. ---
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ARIHANT SSC-PERMUTATIONS & COMBINATIONS -INTRODUCTORY EXERCISE -(19.5 )
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