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Find the number of different words that ...

Find the number of different words that can be formed from 15 consonants and 5 vowels by taking 2 consonants and 4 vowels in each word.

A

625

B

378000

C

525

D

615

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of different words that can be formed from 15 consonants and 5 vowels by taking 2 consonants and 4 vowels, we can follow these steps: ### Step 1: Determine the number of ways to choose consonants We need to select 2 consonants from the 15 available consonants. The number of ways to choose 2 consonants from 15 is given by the combination formula: \[ \text{Number of ways to choose consonants} = \binom{15}{2} \] ### Step 2: Calculate \(\binom{15}{2}\) Using the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] For our case: \[ \binom{15}{2} = \frac{15!}{2!(15-2)!} = \frac{15!}{2! \cdot 13!} \] This simplifies to: \[ \binom{15}{2} = \frac{15 \times 14}{2 \times 1} = \frac{210}{2} = 105 \] ### Step 3: Determine the number of ways to choose vowels Next, we need to select 4 vowels from the 5 available vowels. The number of ways to choose 4 vowels from 5 is given by: \[ \text{Number of ways to choose vowels} = \binom{5}{4} \] ### Step 4: Calculate \(\binom{5}{4}\) Using the combination formula again: \[ \binom{5}{4} = \frac{5!}{4!(5-4)!} = \frac{5!}{4! \cdot 1!} \] This simplifies to: \[ \binom{5}{4} = \frac{5}{1} = 5 \] ### Step 5: Calculate the total number of combinations Now, we multiply the number of ways to choose the consonants by the number of ways to choose the vowels: \[ \text{Total combinations} = \binom{15}{2} \times \binom{5}{4} = 105 \times 5 = 525 \] ### Step 6: Conclusion Thus, the total number of different words that can be formed by taking 2 consonants and 4 vowels is: \[ \text{Total different words} = 525 \] ---
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ARIHANT SSC-PERMUTATIONS & COMBINATIONS -INTRODUCTORY EXERCISE -(19.5 )
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  2. Find the number of diagonals in an n-sided polygon.

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  3. A polygon has 54 diagonals. The number of sides in the polygon is:

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  10. There are n points in a plane out of these points no three are in the ...

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  11. There are n points in a plane no three of which are in the same straig...

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  16. How many words can be formed by using 4 letters at a time out of the l...

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  18. Eighteen guests have to be seated half on each side of a long table. F...

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