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How many words can be formed by using 4 ...

How many words can be formed by using 4 letters at a time out of the letters of the word MATHEMATICS?

A

2445

B

2454

C

1243

D

1454

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many words can be formed by using 4 letters at a time from the letters of the word "MATHEMATICS," we will follow these steps: ### Step 1: Identify the letters and their frequencies The word "MATHEMATICS" consists of the following letters: - M: 2 - A: 2 - T: 2 - H: 1 - E: 1 - I: 1 - C: 1 - S: 1 ### Step 2: Determine the unique letters The unique letters in "MATHEMATICS" are M, A, T, H, E, I, C, S. Thus, we have a total of 8 unique letters. ### Step 3: Calculate the total arrangements for different cases We will consider different cases based on the repetition of letters. #### Case 1: All four letters are different We can choose 4 different letters from the 8 unique letters. The number of ways to choose 4 letters from 8 is given by: \[ \text{Number of ways to choose 4 letters} = \binom{8}{4} \] After choosing 4 letters, we can arrange them in \(4!\) ways. Calculating: \[ \binom{8}{4} = \frac{8!}{4!(8-4)!} = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} = 70 \] \[ 4! = 24 \] Thus, the total arrangements for this case: \[ 70 \times 24 = 1680 \] #### Case 2: Two letters are alike, and two letters are different We can choose one letter that appears twice (M, A, or T), and then choose 2 different letters from the remaining 7 letters. 1. **Choose the letter that appears twice**: There are 3 options (M, A, or T). 2. **Choose 2 different letters from the remaining 7**: \[ \binom{7}{2} = \frac{7 \times 6}{2 \times 1} = 21 \] 3. **Arrange the letters**: The arrangement for 2 alike and 2 different letters is given by: \[ \frac{4!}{2!} = 12 \] Thus, the total arrangements for this case: \[ 3 \times 21 \times 12 = 756 \] #### Case 3: Two pairs of alike letters We can choose 2 letters that appear twice (M, A, or T). The number of ways to choose 2 letters from the 3 pairs is: \[ \binom{3}{2} = 3 \] The arrangement for 2 pairs of alike letters is: \[ \frac{4!}{2! \times 2!} = 6 \] Thus, the total arrangements for this case: \[ 3 \times 6 = 18 \] ### Step 4: Total arrangements Now, we can sum up all the cases: \[ \text{Total} = 1680 + 756 + 18 = 2454 \] ### Final Answer The total number of words that can be formed by using 4 letters at a time from the letters of the word "MATHEMATICS" is **2454**. ---
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ARIHANT SSC-PERMUTATIONS & COMBINATIONS -INTRODUCTORY EXERCISE -(19.5 )
  1. Find the number of diagonals in a decagon.

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  2. Find the number of diagonals in an n-sided polygon.

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  3. A polygon has 54 diagonals. The number of sides in the polygon is:

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  4. Find the number if triangle that can be formed by joining the...

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  5. Find the number of triangle formed by joining 12 different poin...

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  6. Answer these questions based on the following informations Two paralle...

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  7. There are 3 books of mathematics, 4 of science and 5 of literature. Ho...

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  8. if 20 straight line be drawn in a plane , no two of them bei...

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  9. Find the number of different straight lines obtained by joining n poin...

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  10. There are n points in a plane out of these points no three are in the ...

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  11. There are n points in a plane no three of which are in the same straig...

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  12. If m parallel lines in a plane are intersected by a family of n parall...

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  13. In a plane there are 37 straight lines, of which 13 pass through the p...

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  14. Find the number of different words that can be formed from 15 consonan...

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  15. Find the number of ways of selecting 4 letters from the word EXAMINATI...

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  16. How many words can be formed by using 4 letters at a time out of the l...

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  17. In how many ways can 3 ladies and 3 gentlemen be seated around a ro...

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  18. Eighteen guests have to be seated half on each side of a long table. F...

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  19. There are 4 different letters and 4 addressed envelopes. In how many w...

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  20. There are 5 letters and 5 addressed envelopes.The number of ways in wh...

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