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If A and B be two mutually exclusive ...

If A and B be two mutually exclusive events in a sample space such that , `P(A) = 2/5 and P(B) = 1/2 ` then
find `P ( barA nn B )`:

A

`1/2`

B

`3/5`

C

`4/7`

D

`7/15`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the probability of the complement of the intersection of two mutually exclusive events A and B. Let's break it down step by step. ### Step 1: Understand Mutually Exclusive Events Mutually exclusive events are events that cannot occur at the same time. This means that the probability of both events A and B occurring simultaneously is zero: \[ P(A \cap B) = 0 \] ### Step 2: Given Probabilities We are given: \[ P(A) = \frac{2}{5} \] \[ P(B) = \frac{1}{2} \] ### Step 3: Find the Probability of the Intersection Since A and B are mutually exclusive, the probability of their intersection is: \[ P(A \cap B) = 0 \] ### Step 4: Find the Probability of the Complement of the Intersection We need to find \( P(\bar{A} \cap B) \). The complement of the intersection can be expressed as: \[ P(\bar{A} \cap B) = P(B) - P(A \cap B) \] ### Step 5: Substitute the Values Now substituting the values we have: \[ P(\bar{A} \cap B) = P(B) - P(A \cap B) \] \[ P(\bar{A} \cap B) = \frac{1}{2} - 0 \] \[ P(\bar{A} \cap B) = \frac{1}{2} \] ### Final Answer Thus, the probability of the complement of A intersection B is: \[ P(\bar{A} \cap B) = \frac{1}{2} \] ---
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ARIHANT SSC-PROBABILITY-INTRODUCTORY EXERCISE -(20.2)
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