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A natural number is chosen at random fro...

A natural number is chosen at random from the first 100 natural numbers. What is the probability that the number chosen is a multiple of 2 or 3 or 5?

A

`30/100`

B

`1/33`

C

`74/100`

D

`7/10`

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AI Generated Solution

The correct Answer is:
To find the probability that a randomly chosen natural number from the first 100 natural numbers is a multiple of 2, 3, or 5, we can use the principle of inclusion-exclusion. Here are the steps to solve the problem: ### Step 1: Define the Sets Let: - \( A \) = Set of multiples of 2 - \( B \) = Set of multiples of 3 - \( C \) = Set of multiples of 5 ### Step 2: Calculate the Size of Each Set 1. **Multiples of 2**: \[ |A| = \left\lfloor \frac{100}{2} \right\rfloor = 50 \] 2. **Multiples of 3**: \[ |B| = \left\lfloor \frac{100}{3} \right\rfloor = 33 \] 3. **Multiples of 5**: \[ |C| = \left\lfloor \frac{100}{5} \right\rfloor = 20 \] ### Step 3: Calculate the Size of the Intersections 1. **Multiples of both 2 and 3 (i.e., multiples of 6)**: \[ |A \cap B| = \left\lfloor \frac{100}{6} \right\rfloor = 16 \] 2. **Multiples of both 3 and 5 (i.e., multiples of 15)**: \[ |B \cap C| = \left\lfloor \frac{100}{15} \right\rfloor = 6 \] 3. **Multiples of both 2 and 5 (i.e., multiples of 10)**: \[ |A \cap C| = \left\lfloor \frac{100}{10} \right\rfloor = 10 \] 4. **Multiples of 2, 3, and 5 (i.e., multiples of 30)**: \[ |A \cap B \cap C| = \left\lfloor \frac{100}{30} \right\rfloor = 3 \] ### Step 4: Apply the Inclusion-Exclusion Principle To find the total number of favorable outcomes (i.e., multiples of 2, 3, or 5), we use the formula: \[ |A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |B \cap C| - |A \cap C| + |A \cap B \cap C| \] Substituting the values we calculated: \[ |A \cup B \cup C| = 50 + 33 + 20 - 16 - 6 - 10 + 3 \] \[ |A \cup B \cup C| = 103 - 32 = 71 \] ### Step 5: Calculate the Probability The probability \( P \) that a randomly chosen number is a multiple of 2, 3, or 5 is given by: \[ P = \frac{|A \cup B \cup C|}{100} = \frac{71}{100} \] ### Final Answer Thus, the probability that the number chosen is a multiple of 2, 3, or 5 is: \[ \frac{71}{100} \] ---
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