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A speaks truth in 60% cases and B speaks...

A speaks truth in 60% cases and B speaks truth in 70% cases. The probability that they will say the same thing while describing a single event is:

A

a. `0.36`

B

b. `0.54`

C

c. `0.48`

D

d. `0.20`

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The correct Answer is:
To find the probability that A and B will say the same thing while describing a single event, we need to consider two scenarios: 1. Both A and B tell the truth. 2. Both A and B tell a lie. Let's denote: - P(A tells the truth) = 0.6 (60%) - P(A tells a lie) = 1 - P(A tells the truth) = 1 - 0.6 = 0.4 (40%) - P(B tells the truth) = 0.7 (70%) - P(B tells a lie) = 1 - P(B tells the truth) = 1 - 0.7 = 0.3 (30%) ### Step 1: Calculate the probability that both A and B tell the truth. The probability that both A and B tell the truth can be calculated by multiplying their individual probabilities of telling the truth: \[ P(A \text{ tells the truth}) \times P(B \text{ tells the truth}) = 0.6 \times 0.7 = 0.42 \] ### Step 2: Calculate the probability that both A and B tell a lie. Similarly, the probability that both A and B tell a lie can be calculated by multiplying their individual probabilities of telling a lie: \[ P(A \text{ tells a lie}) \times P(B \text{ tells a lie}) = 0.4 \times 0.3 = 0.12 \] ### Step 3: Add the probabilities from Step 1 and Step 2. To find the total probability that A and B say the same thing (either both tell the truth or both tell a lie), we add the probabilities from Step 1 and Step 2: \[ P(\text{same}) = P(A \text{ tells the truth}) \times P(B \text{ tells the truth}) + P(A \text{ tells a lie}) \times P(B \text{ tells a lie}) \] \[ P(\text{same}) = 0.42 + 0.12 = 0.54 \] ### Final Answer: The probability that A and B will say the same thing while describing a single event is **0.54**. ---
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