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A pack of cards consists of 15 cards num...

A pack of cards consists of 15 cards numbered 1 to 15. Three cards are drawn at random with replacement. Then, the probability of getting two odd and one even numbered cards, is?

A

a. `3/1430`

B

b. `100/2430`

C

c. `448/1125`

D

d. `7/72`

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability of drawing two odd and one even numbered card from a pack of 15 cards numbered 1 to 15, we can follow these steps: ### Step 1: Identify the total number of odd and even cards - The cards numbered from 1 to 15 include: - Odd numbers: 1, 3, 5, 7, 9, 11, 13, 15 (Total: 8 odd cards) - Even numbers: 2, 4, 6, 8, 10, 12, 14 (Total: 7 even cards) ### Step 2: Determine the total number of cards - Total cards = 15 (8 odd + 7 even) ### Step 3: Calculate the probability of drawing two odd and one even card Since the draws are with replacement, the probability remains constant for each draw. - Probability of drawing an odd card (P(Odd)) = Number of odd cards / Total cards = 8/15 - Probability of drawing an even card (P(Even)) = Number of even cards / Total cards = 7/15 ### Step 4: Determine the different arrangements of drawing two odd and one even card The possible arrangements for drawing two odd and one even card can be represented as: - OOE, OEO, EOO ### Step 5: Calculate the probability for one arrangement For one arrangement (e.g., OOE): - Probability = P(Odd) × P(Odd) × P(Even) - Probability = (8/15) × (8/15) × (7/15) ### Step 6: Calculate the total probability for all arrangements Since there are 3 arrangements (OOE, OEO, EOO), we multiply the probability of one arrangement by the number of arrangements: - Total Probability = 3 × [(8/15) × (8/15) × (7/15)] ### Step 7: Simplify the expression - Total Probability = 3 × [(64/225) × (7/15)] - Total Probability = 3 × (448/3375) - Total Probability = 1344/3375 ### Step 8: Final Result The probability of getting two odd and one even numbered card is: - **Probability = 1344/3375**
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