+4+7+11+16+" to "n" terms "=

Prove the following by the method of induction for all n in N : 3 + 7+ 11 +.. to n terms = n(2n + 1).

2 + 4 + 7 + 11 + 16 + .... to n term =

if (3 +5+7+9+…. " up to 35 terms " )/(5+8+11+ …. " up to n terms ")=7 , find the value of n.

2+ 4+ 7 + 11 + 16 + ….. upto n terms is equal to

If S_1 = 3, 7, 11 15, … upto 125 terms and S_2 = 4, 7, 10, 13, 16, … upto 125 terms the how many terms are there in S_1 that are there in S_2 ?

1/2+3/4+7/8+15/16+..... t o n terms =

If S_n = (1)/(6.11) + (1)/(11.16) + (1)/(16.21) + …. to n terms then 6S_n equals

lim_(n to infty) ((1)/(3.7)+(1)/(7.11) +(1)/(11.15)+. . . +(n" terms ")) =