A person throws balls into the air one after the other at an interval ofone second. The next ball is thrown when the velocityof the ball thrown earlier is zero. To what height the ball rise:

A man throw rings into air one after the other at an interval of one second. The next ring is thrown when the velocity of the ring thrown earlier is zero. The height to which the ring rise is ("take" g = 10ms^(-2))

A person throws balls into air vertically upward in regular intervals of time of one second . The next ball is thrown when the velocity of the ball thrown earlier becomes zero . The height to which the balls rise is … (Assume , g = 10 ms^(-2) )

A boy throws balls into air at regular interval of 2 second. The next ball is thrown when the velocity of first ball is zero. How high do the ball rise above his hand? [Take g=9.8m//s^(2) ]

A boy throws balls into air at regular interval of 2 second. The next ball is thrown when the velocity of first ball is zero. How high do the ball rise above his hand? [Take g=9.8m//s^(2) ]

A man throws ball into the air one after the other. Throwing one when other is at the highest point. How high the balls rise if he throws twice a second.

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 second. What should be the speed of the throw so that two balls are in the sky at any time?

A man is standing on top of a building 100 m high. He throws two ball vertically, one at t=0 and after a time interval (less than 2 seconds). The later ball is thrown at a velocity of half the first. At t=2 , both the balls reach to their and second ball is +15m . Q. The time interval between the throw of ball is

A man throws balls into air one after another throwing one the other is at the highest point. How high the balls rise , if he throws twice a second ?