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A man runs along a horizontal road holdi...

A man runs along a horizontal road holding his umrella vertical in order to afford maximum protection form rain. The rain is actually.

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A man runs along a horizontal road on a rainy day. His umbrella vertical in order to protect himself from the rain then rain actually

A boy is running on a horizontal road with a velocity of 5 m/s. At what angle should he hold his umbrella in order to protect him self from the rain if the rain is falling vertically with a velocity of 10 m/s?

A boy is running on a horizontal road with a velocity of 5 m/s. At what angle should he hold his umbrella in order to protect him self from the rain if the rain is falling vertically with a velocity of 10 m/s?

A man running on a horizontal road at 6 km//h finds the rain falling vertically. He doubles his speed and find that the raindrops make an angle 37^(@) with the vertical. Find the velocity of rain with respect to the ground.

Statement -1 : A man standing on the ground has to hold his umbrella at an angle theta with the vertical to protect himself from rain. It is possible that the man now starts running on the ground with certain speed, but he still has to hold his umbrella at angle theta with the vertical to protect himself from rain. Statement -2 : Vertical component of velocity of rain w.r.t man does not change. if he starts running on a horizontal ground.

Statement -1 : A man standing on the ground has to hold his umbrella at an angle theta with the vertical to protect himself from rain. It is possible that the man now starts running on the ground with certain speed, but he still has to hold his umbrella at angle theta with the vertical to protect himself from rain. Statement -2 : Vertical component of velocity of rain w.r.t man does not change. if he starts running on a horizontal ground.

A man is going in a topless car with a velocity of 10.8kmph."l It is raining vertically downwards.He has to hold the umbrella at angle 53^(0) to the vertical to protect himself from rain.The actual velocity of the rain is (cos53^(0)=(3)/(5))