A photon of frequency v is incident on a metal surface whose threshold frequency is `v_(0)`. The kinetic energy of the emitted photoelectrons will be

Light of frequency 4 v_(0) is incident on the metal of the threshold frequency v_(0) . The maximum kinetic energy of the emitted photoelectrons is

Light of frequency 4nu_0 is incident on the metal of the threshold frequency nu_0 . The maximum kinetic energy of the emitted photoelectric is

Photons of frequency, v, fall on metal surface for which the threshold frequency is v_(0) . Then

Light of frequency v is incident on a substance of threshold frequency v(v lt v) . The energy of the emitted photo-electron will be

A photon of energy 10 eV is incident on a metal surface of threshold frequency 1.6 xx 10^15 Hz . The kinetic energy of the photoelectron (in eV) is (assume h = 6 x 10^-34 )

Radiation of frequency v=9v_(0) is incident on a metal surface, having threshold frequency v_(0) . The maximum velocity of the ejected photoelectrons is 6xx10^(6)m//s . What will be the maximum velocity of the ejected photoelectrons , if v is reduced to 3v_(0) ?

A photon of energy 8 eV is incident on metal surface of threshold frequency 1.6 xx 10^(15) Hz , The maximum kinetic energy of the photoelectrons emitted ( in eV ) (Take h = 6 xx 10^(-34) Js ).