" If "cos theta cos2 theta*cos3 theta=1/4" then "theta=

4cos6 theta cos4 theta cos2 theta=

1+cos2 theta+cos4 theta+cos6 theta=

If cos theta + cos 2theta + cos 3theta = 0 then theta =

Solve : cos theta cos 2 theta cos 3 theta =(1)/(4) (0 le theta le pi)

cos 4theta = cos 3theta - cos2theta

If cos theta cos 2 theta cos 3theta = 1//4 for 0 lt theta lt pi then theta =

If cos2 theta*cos3 theta*cos theta=(1)/(4) for 0

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

Prove that, If " "15 theta = pi, "show that," cos theta cos2 theta cos3theta cos 4theta cos5 theta cos6theta cos7theta =1/2^(7)

If theta=(pi)/(9), prove that cos theta cos2 theta cos3 theta cos4 theta=(1)/(16)